THE Description and Use Of an Ordinary JOYNT-RULE Fitted with LINES For the ready finding The Lengths and Angles of Rafters and Hips, and Collar-Beams in any Square or Bevilling Roofs at any Pitch, and the Ready Drawing the Architrave, Freeze and Cornice in any Order.  
WITH Other Useful Conclusions by the said Rule.  
By John Browne.  
LONDON: Printed for William Fisher at the Postern Gate near Tower-Hill. 1669.   

The Description and Use of a joint-rule fitted with Lines for the ready finding the Lengths and Angles of Rafters, Hips, and Collar Beams in any Square or Bevelling Roofs at any Pitch.  
FIrst, The Rule is an ordinary Jointed Rule of a foot long when shut together, or two foot being opened to a straight Line. And the Lines delineated thereon for this purpose, are  
1. First, a Line of Lines, drawn Sector-wise from a centre on both legs of the Rule, but continued to 30 at the end in stead of 10 the old usual manner, and every fingle Integer of the 30 is divided into 12 parts, to represent every particular inch of the 30 foot according to the common reckoning by feet and inches.  
2. There is another Scale of equal parts also, of the same length lying as near to the other of 30 as may be, on one leg only, which is divided into 40 parts, to represent 40 feet: and each of those 40 feet, parted into 6 parts to represent every two inches only, because the room for one foot, will not admit of more parts.  
3. In the same place on the other leg is divided a Line of natural Sins and Tangents to 45, but numbered as a Line of Chords to 180 Degrees, to set the Rule to, or to find the quantity of any Angle, in the proper terms of expression (all the world over) degrees and minutes.  
4, On the innermost Line of the 30 Scale that runs to the Centre is set 20 pricks, beginning at 2 at the Center-pin at 30, and so proceeding with 3, 4, 5, and 6 at the Center-pin at 15, and then 7, 8, 9, 10, and so forwards to 20, towards the Centre, which serves to divide a Circle into any number of parts, very useful and ready in the practice of Drawing or Architecture.  
Thus much for Description, the Uses follow.  
The uses of this Line of Lines, or Scale of equal Parts to 30, drawn from the Centre is of a general and manifold use: as Mr. Gunter in his Book of the Sector hath showed.  
A brief touch whereof take in the first place, as by the way, and then the use of the Rule to the business intended.  
And for the better doing hereof, it is needful to explain three or four terms, for the avoiding of many words, and needless repetitions in this brief, yet plain Discourse.  
1. First by the word Lateral is meant any distance taken, either in feet and inches, on the 30 Scale; or degrees and minutes on the Chords, taken and counted from the Centre, in the midst of the head of the joint-rule, a long any one leg: as thus; Suppose I would take out 15 foot Laterally, set on point of the Compasses in the Centre at the head, and open the other to 15 on any one Leg on the 30 Scale; this extent I call a Lateral Extent of 15 foot. Also if you taketh Lateral Chord of 60 Degrees you shall find the extent of the Compasses from the Centre to 60 to be the same as from the Centre to 15 foot, on the 30 Scale of Feet and Inches.  
2. By the word Parallel, I mean any distance taken, by setting one point of the Compasses in any number of feet and inches on one Leg, and the other point in the same, or any other number on the other Leg, across from one Leg to the other; as thus the Rule being opened then the extent of the Compasses from 20 on one Leg, to 20 on the other Leg, is a Parallel extent.  
3. In all Parallel Extents, you must set one point of the Compasses in the Common Line on one Leg, to the Common Line on the other Leg, which Common Line is that only of the 30 Scale which runs to the Centre, in which the Center-pins at 15 and 30 are.  
4. The nearest distance from a point to a Line is only thus: Set one point of the Compasses in the point given, and open or shut the other being turned about, till the other will but just touch or cleave the Line, that I call the nearest distance.  

Use I.  
To lay down a line, that shall represent any Number of Feet and Inches given or required.  
Take the Number given laterally from the 30, or 40 Scale from the Centre, and that is the Line required.  
But if these Scales are too great, or too small, then take your Number of parts and the length thereof Laterally.  
As for Example suppose I would have 3 Inches to represent 30 Foot, take out 3 Inches between your Compasses, and make it a parallel in 30 and 30, and the 30 Scale is set to your desire.   

Use II.  
To Increase or Diminish a Line to any Proportion.  
Take the given Line between your Compasses, and make it a parallel in the parts thereof; then the parallel extent of the parts you would have it Increased, or Diminished to, is the Augmentation, or Diminution, which was required.  
Example.  
Let 3 Inches represent 8 foot, and to the same proportion I would have 10 Foot, or 5 foot, viz. more, or less.  
Take 3 Inches between your Compasses, and make it a parallel in 8, and 8 on the 30 Scale; then the parallel distance between 5 and 5, doth diminish the Line, and the parallel between 10 & 10 doth Increase the Line to the proportion required.   

Use III.  
To divide a Line into any Number of parts or models under 30.  
Take the given Line, and make it a parallel in the parts on the 30 Scale into which you would have it divided, than the parallel extent between 1 and 1 shall divide the Line accordingly, Example.  
Let 4 Inches be a Line to be divided into 9 parts, take 4 Inches (or any distance whatsoever) and make it a parallel in 9 and 9 on the 30 Scale; then the parallel distance between 1 and 1 shall divide 4 Inches into 9 parts required: Note, that for more exactness and conveniency, you may Double 9, or Triple 9, viz. 18, or 27. and then if you make the Line to be divided, a parallel in Triple the Number you must take out 3 in stead of one, and that shall divide the Line into the parts required.  
Example, I would have 5 Inches put into 10 parts, take 5 Inches between your compasses and make it a parallel in 30 and 30 the Triple of 10, then take out parallel 3, and 3 the triple of one: and that shall divide the Line given being 5 Inches into 10 parts or models exactly: the like for any other. And note as the Rule stands you may take out any number of parts or models whatsoever, to that Scale.   

Use IU.  
Any two Lines given, to find their Proportion one to another according to any other Number.  
That the Lines severally, and lay them Laterally from the Centre, on the 30 or the 40 Scale, which you please; and the Numbers of Feet and Inches, to which they reach, shall show their proportion one to another of the parts of the Line on which they are measured.  
Example, I have 2 Lines suppose one is 2 Inches long, and the other 5 or any other unknown part.  
Take 2 Inches the measure of one Line, and measure it Laterally on the 30 Scale, and it gives 5 Foot ½ an Inch, then take out 5 Inches the supposed length of the other Line, and it gives Laterally 12 Foot 8 Inches; then I say one Line is 5 Foot and half an Inch, and the other is 12 Foot 8 Inches of a Scale of 30 Foot in 11 Inches 3 quarters length.  
Or if you conclude on the Term or number of one Line, then make that Line a parallel in the parts thereof, then take the other Line, and carry it parallelly till it stay in like parts, on both Legs in the common Line, and that shall be the Denomination of the other Line.   

Use V.  
Two Lines being given to find a Third in continual Proportion to them.  
Take both the Lines, and lay them laterally on both Legs, and note the feet and inches to which they do extend as in the last.  
Then take out the lateral extent of the second Line, and make a parallel in the terms of the first Line, keeping the common Line at that opening, than the parallel extent from the terms of the second Line, shall be the lateral 3d Term or Line in Proportion. Example,  
Suppose I have one Line 3 foot long, and another 5 foot, and I would have another to bear proportion to 5, as 3 doth to 5 increasing, being in numbers thus; as 3 is to 5, so is 5 to what? Here note that 3 is the first number, and 5 the second.  
3. The first Line laid from the Centre, on the 30 Scale, extends to 7 foot 7 inches, and 5 inches, the second Line gives 12 foot 8 inches.  
Now the lateral second Line, viz. 5. or 12 foot 8 inches, made a parallel in 7 foot 7 inches the terms of the first Line, then take out the parallel extent from 12 foot 8 inches (the measure of 5) and it shall give 21 foot 1 inch laid laterally from the Centre, for a third Proportional required; which, measured on the inches, is 8 inches and a third, the answer required; for as 3 is in proportion to 5, so is 5 to 8 and a third part.  
But by the Line of Numbers, having the Quantity of the Lines given in Numbers, do thus;  
The Extent of the Compasses from the first Number 3, to the second Number 5, shall reach the same way from the second Number 5, to 8. 33 the third Proportional Number required.   

Use VI.  
To divide a Line in such sort as another Line is divided.  
Take the whole Line that is divided, and lay it laterally yond both Legs, and fit the Line that is to be divided parallelly in the ends thereof, then lay every part of the divided Line laterally in like manner, as the whole Line was laid, and the parallel extent between those parts shall divide the Line accordingly: as for Example;  
Suppose I would divide a Line of 8 inches ¾ long in such sort as the Line of Circles on the inside of the 30 Scale is divided.  
Take out 8 inches ¾, and make it a parallel in 2 and 2, the divided Line, then take out the parallel distance from 3 and 3, and that shall give the Point 3 from the end of the Line you would divide, and so consequently all the rest in order. As far as you please.   

Use VII.  
To find a Mean Proportional between two Lines or Numbers.  
Open the 30 Scale to a right Angle, by making Lateral 21 foot 2 inches a parallel in 15 foot.  
Then find the Sum and half Sum, the Difference and half Difference, between your two Numbers; and having the half Sum between your Compasses, set one Point to the half Difference counted laterally on one Leg; and wheresoever the other Point shall touch the Common Line on the other Leg, is the mean Proportional required. Example.  
Suppose a piece of Timber be 10 inches one way, and 18 inches another, what is the Square equal, which is the Mean Proportional between them? the sum of 10 and 18 is 28, the half sum is 14, the difference between 10 and 18 is 8, the half difference is 4. Now the 30 Scale standing Square, taking 14 the half Sum between your Compasses, and then fet one Point in 4 on one Leg; and turn the other Point of the Compasses toward the Common Line, and there it shall show 13 5/12 near the Square equal required.   

Use VIII.  
To work the Rule of Three by the Line of Lines to 30, or to 3 Numbers given to find a fourth, in Geometrical Proportion Direct.  
Make the lateral second, a parallel in the first, than the parallel third shall give the lateral fourth number required. Example;  
If one foot of Timber cost 10 d. what shall 6 foot cost? facit 60 d.  
Make Lateral 10 a Parallel in 10 counted as 1, than the Parallel Extent between 6 and 6 shall reach to Lateral 60, the Answer required, (in pence).  
Again, another Example:  
If 50 Foot, or a load of Timber cost 44 s, what shall one Foot cost?  
Take the Lateral Extent from 22 the half of 44 s, and make it a Parallel in 25 the half of 50, than the Parallel distance between 2 and 2 counted as 4 foot shall give the Lateral Number of 3 s. 6 d. the price of 4 foot, whose fourth part is 10 d. ½ the price of one foot. Note this help is used, to avoid the nearness to the centre where the work is inconvenient.   

Use IX.  
To measure Flat Measure by the Scale of 30.  
At any inches broad to find how much in length makes a foot.  
Take Lateral 12, make it a Parallel in the breadth given, then take out Parallel 12 again, and it shall give the length of a foot required.  
Example, At 9 Inches broad, as Lateral 12, to Parallel 9, so is parallel 12, to Lateral 16, the length required.   

Use X.  
The breadth of a Board given in Inches, and the length in Feet, to find the Content in Feet and Inches required.  
Take the Lateral length in feet, and make it a Parallel in 12, than the Lateral distance, between the Inches broad, shall give the Parallel Content.  
Example, Of 15 foot 3 inches long, and 9 inches broad.  
Take Lateral 15 foot 3 inches, and make it a Parallel in 12, then take out Parallel 9 and 9, and it shall give Lateral 11, foot and a half, the Content.   

Use XI.  
To Measure Timber by the Line of Lines to 30.  
At any Inches Square to find how much makes a Foot of Timber.  
If the Piece be not Square, then by the 8th Use make it Square: Then thus;  
Take the Lateral Side of the Square in Inches, make it a Parallel in 12, then take out the Parallel Side of the Square, and it shall give a Lateral 4th Number.  
Then take out Lateral 12, and make it a parallel in the 4th number, and then take out Parallel 12 again, and it shall show the answer in Inches laid Laterally from the Centre.  
Example, At 9 Inches Square what makes a Foot?  
As lat. 9 to par. 12, so is par. 9 to lat. 6 ¾: Agair,  
As lat. 12, to par. 4th viz. 6 ¾, so is par. 12, to 21 inches ¼ the length to make one foot required.   

Use XII.  
The Inches Square, and Length given in Feet, to find the Content in Feet and Inches.  
As the Lat. Side of the Square, to parallel 12 so is the parlength to a lat. 4th: Again,  
As the la●. 4th to parallel 12, so is the par. side of the Square, to Lateral Content.  
Example, at 9 Inches Square and 20 Foot long.  
As lat. 9 to par. 12, so is par. 20 to lateral 15, a 4th number: Again,  
As lat. 15 the 4th, to par. 12: So is parallel 9, to lat. 11 ¼, the Content required.  
Thus much for the General Use, being too long a Digression from the matter mainly intended.   

Use XIII.  
The Breadth of any Frame being given, to find the Length of the Rafter and Perpendicular by Inspection only.  
It being a General received Rule, that the length of the Rafters should be three quarters the breadth of the House (or frame) for true pitch, and 40 the feet in one Scale, being equal in length to 30 the Number of feet in another Scale, and 30 being 3 quarters of 40. Therefore,  
If you seek for the breadth of the house on the 40 Scale, then right against it, on the 30 Scale, is the length of the Rafter required. Also if you seek the length of the Rafter on the 40 Scale, on the 30 Scale, right against it, is the height of the perpendicular required, viz. from the Raising-piece to the top of the Gable end or Rafter required.  
Example, If a house be 30 foot broad, the Rafter ought to be 22 foot 6 Inches, and the perpendicular 16 foot 9 Inches and a ½, for right against 30, counted on the 40 Scale, on the 30 Scale is 22- 6 the Rafter, and right against 22- 6 on the 40 Scale on the 30 is 16- 9 ½ the perpendicular.  
1. Also by the Line of Numbers, the extent of the Compasses, from 20 to 15, will reach the same way from the breadth of any house to his proportionable Rafter at true pitch.  
2. And the extent, from 20 to 18, turned the same way from any breadth of a house to his proportionable Hip Rafter, in square frames.  
3. Also the extent from 20 to 11 18/100 will reach the same way from the width of any house to his proportionable perpendicular, at square and true pitch.  
4. And the extent from 20 to 28- 28, will reach from any other house breadth to his proportional whole Diagonal Line required, at square and true pitch.  
5. And the extent from 20 the breadth to 16- 63 the nearest distance at that breadth, shall reach from any other breadth to his proportional nearest distance required, if it were needful. But the Angles in all Roofs great or small, if true pitch and square, are the same in all Frames.   

Use XIV.  
The breadth of the house and the height of the Perpendicular being given to find the Rafters length, the Hips Length, the Diagonal Line, from Corner to the King-post, and any Angle required, in Square Frames. What the perpendicular height of the Gable end aught to be at true pitch by the last Rule you may readily see, and the better make estimate of the quantity of alteration. Which being once Resolved on, then thus proceed,  
First open the two 30. Scales to a Right Angle by making Lateral 21 Foot 2 Inches ½ a parallel in 15, & 15 in the Brass Centre pins.  
1. Then count half the breadth of the house on one Leg, and the Length of the Perpendicular resolved on, on the other leg, than the parallel distance between them, measured Laterally from the Centre, shall give the true length of the Rafter required. 
Rafter.   
2. For the Hips Length count the Length of the Rafter last found on one Leg, and the half breadth of the house on 
Hips.  the other Leg, and take the parallel distance between, and measure it from the Centre, Laterally, and it shall be the true Length of the Hips required.  
3. For the Diagonal Line, count the half breadth of the 
Diagonal.  house on both Legs, and take the parallel distance between, and measure it from the Centre, and it shall be the Length of the Diagonal Line, from the Corner to the King-Post.  
4. Again for the Hips count the Diagonal Line last found 
Hips Length.  on one leg, and the perpendicular height on the other Leg, and the parallel distance between shall be the Hips true Length measured us before from the Centre.  
Example, in a house of 20 Foot wide at true pitch. See fig. 1. let A B C D represent a frame of a house 20 Foot wide, B I the half width, B A and C D equal to B C the whole width being 2 points to draw the Diagonal Lines by. I E being equal to I B, and the half E I laid from E to G giveth I G the true length of the Rafters, and G B or G C the Length of the Hips.  
Or thus, Three quarters of C B, viz. C H, giveth C F and B F, the Rafters Length: the same extent also laid upon the middle Line from I to G, giveth CG and BG the Hips Length. IF is the perpendicular height, E is the point of the Diagonal Line or King-post, perpendicularly opposite to or right under the meeting point of the 2 Hips, and the two Rafters, when raised and set in their places.  
Thus much for Illustration what to do, now for Application how to do.  
The width of the house is always given, the Length of the Rafter; or the height of the perpendicular is next resolved on, which in our Example being true pitch is also resolved on, either by inspection as before, or else by operation in this manner.  
1. The Breadth of the house being 20 Foot, and the perpendicular resolved on to be 11 Foot 2 Inches ½ To find the Rafters Length, work thus,  
Open the 30 Scale to a Right Angle (by use the 7th) count 10 the half breadth of the house on one Leg, and the 
For the Rafters length.  perpendicular height 11 2 ½ on the other Leg. (viz. both on the 30 Scale from the Centre) and take the parallel distance between them, (on the common Line) and measure it from the Centre, and it shall give just 15 Foot the length of the Rafter required C F.  
2. But if according to the width of any frame, you resolve on the Rafters length, and would have the perpendicular height of the Gable end, than thus,  
Count the length of the Rafter from the Centre, and take the lateral extent thereof (being 15) between your Compasses, the Compasses being so set, set one point in 10 
For the Perpendicular.  the half width of the frame, and turn the other point parallelly to the common Line, and there it shall show 11 Foot 2 1/7 Inches, the true height of the perpendicular at true pitch required. I F 11 Foot 2 Inches 1/7.  
3. For the Length of the Hips, Count the half breadth of the house on one Leg, and the Rafters length on the other Leg, and take the parallel distance between, and it shall give the true length of the Hips required. As here, the parallel 
For the Lips Length.  distance between 15 and 10, shall be lateral 18, the true length of the Hips required in a square frame 20 foot wide true pitch. C G  
4. For the Diagonal line from the Corner to the King-post.  
Count the half width of the house, viz. 10 Foot on both 
Half the Diagonal Line.  Legs, and take the parallel extent between, and it shall reach from the Centre to 14 foot 1 Inch ⅝ being the line C E in the figure.  
5. Otherwise for the Hips length, Count the half Diagonal on one Leg 14 1 ⅝ and the perpendicular 11 foot 2 In. 
Hip.  Inches 2 2/7 on the other Leg, and the parallel distance between, measured from the Centre, will give the true Hips length 18, viz. the line C G.  
Thus much for the Rafters and Hips in square frames at true pitch, the measure of whose Angles and Lengths are as followeth,    F. Inc. 100 parts F. 100 parts.  deg. min. The breadth of the house being 20 f. and the two ends square, and the Rafters at true pitch, the Lengths and angles of the frames, are C F Rafter 15 00 00 15 000 Rafter Top 41 50 C G Hip 18 00 00 18 000 Foot 48 10 I F Perpendicular 11 02 17 11 180 Hips Top 51 38 B E ½ Diagonal 14 01 68 14 140 Foot 38 22 B I Half Breadth 10 00 00 10 000    B C Whole Breadt. 20 00 00 20 000 Difference 13 16 K G Nearest D●st. 16 07 50 16 624     B D Whole Diagoras. 28 03 36 28 281 Outsid. Ang. 116 12  

The Rule to find the Angles of the Rafters and Hips.  
1. For the Angles that the Rafters make at Foot, and Head, with the Raising-piece and King-post, do thus,  
When the Rule stands square in the 30 Scale, then lay any straight piece to the Compass points, when one stands in the half breadth, and the other point in the perpendicular; then if you apply a Bevel severally, to that straight edge, and the 30 Scale at each end, the one is the Angle at Foot 48- 10, and the other the Angle at Head, viz. 41- 50.  
2. For the Angle at Head or King-post and foot of the Hips, do thus, the 30 Scale being set square, set one point of the Compasses in the half Diagonal-line; on one 30 Scale, and the other point in the perpendicular on the other 30 Scale, and to those points lay any straight piece, than set a Bevel to that Straight piece, and each 30 Scale, and the one shall be the Angle at Foot 38- 22, and the other the Angle at the head, viz. 51- 38; then this last Angle doubled, and the difference between the Angle at Head, and Foot, viz. 13- 16 added, makes 116- 12 the Angle of the outside of the Hip-rafter in a square frame at true pitch required.  
3. A General way to find this outward Angle of the Hip or mould is thus, in any pitch.  
First, you must find the nearest distance from one corner to the opposite Hippolito set up, or from a point in the raising piece, as far from one corner as the house end is broad, as the point K or L in the Figure may be done thus,  
Count the length of the Hip on one Leg, (and also take it between your Compasses) and count the breadth of the house on the other Leg, and set one point of the Compasses in the Hips length on one Leg, and the other point in the breadth of the house on the other Leg altering the 30 Scales, but not your Compasses; then when the 30 Scales are so set, one represents the Raising piece, and the other the Hip set up.  
Then the nearest distance from the breadth of the house on one 30 Scale, to the Common-line on the other 30 Scale, is the nearest distance required being measured from the Centre, 16- 7- ½  
Then take the whole Diagonal Line, viz. C L, or B K from the Centre Laterally, and make it a parallel, in the nearest distance last found; and that shall set the 30 Scales to the Angle of the outside of the Hip required, which you may measure in degrees thus: take parallel 15 as the Rule stands, and lay it from the Centre, and it shall reach to 116 Degrees on the Chords, next one 30 Scale, the Angle of the outside of the Hips required.  
Example and more briefly in a House 20 Foot broad.  
The house end is 20 Foot broad the whole Diagonal Line is 28 foot 3 inches ⅜, the Hip Rafter 18 Foot.  
Take 18 Foot between your compasses, and set one point in 20, and open or shut the Rule till the other fits 18, than the nearest distance from 20 to the Common Line will be 16 foot 7 inches 4/8.  
Then take 28 foot 3 inches ⅝, the whole Diagonal Line, and make it a parallel in 16 foot 7 inches ½ the nearest distance, and the 30 Scales are set to the Angles required: For,  
If you take out Parallel 15 the Chord of 60, and measure it Laterally from the Centre, it shall reach to 116, the Angle in Degrees and Minutes required.  
Note, If the whole breadth and whole Diagonal Line is too large for your Compasses, than the half breadth and half Diagonal will do as well, (taking the half length of the Hip also between your Compasses, and on the Scale also) and that shall set the Scales to the same Angle as before.    

Use XV.  
To find the Lengths and Angles of the Rafters and Hips, or Sleepers, in Bevelling Frames at any Pitch.  
1. For the length of the Rafter, set the 30 Scales square, then count the half length of the bevel-end on one Leg, (being always more there than the half breadth) and the Perpendicular resolved on, on the other Leg; Then the Parallel distance between, measured laterally, shall be the length of 
Rafter.  the Rafter required, and a Ruler laid to the two Points of the Compasses so set on the 30 Scales, and a Bevel set, as before in Square Frames is showed, shall give the Angles at head and foot required.  
2. For the Hips length, count the Rafters length on one Leg, and the half breadth of the bevel-end of the House, more by half the number of inches bevelling on the other Leg, and take the parallel distance between, and Measure it Laterally 
Hips.  from the Centre, and it shall be the length of the longest Hip-Rafter. And for the shortest Hip count less than the Bevel-end, by half the number of Inches bevelling, and that shall be the short Hip required.  
3. The Inches, or Feet and Inches of Bevelling being given, to find how much one corner is under, and the other over 90 Degrees (or just Square) open the 30 Scales, and take the breadth of the House over at the nearest distance, between 
Angle of the Frame.  your Compasses, from the 30 Scale from the Centre laterally, and make it a parallel in 15 and 15 for 60 of the Chords.  
Then take the Feet and Inches Bevelling from the same 30 Scale laterally, and carry it parallelly till it stay in like parts; then just against it on the Degrees or Tangents are the Degrees and Minutes required, that one corner is more, and the other less than 90 Degrees.  
4. To find the Diagonal Line.  
Take the distance in the Chords to the Degrees above, or under 90 last found, from the Centre Laterally, and make it a Parallel in 15 and 15, and then the 30 Scales are set to the Angle; the end is over, or under 90 Degrees: Then count 
Diagonal Lines.  the whole or half Bevel end on both Legs, and the Parallel distance between shall show the length of the whole, or half Diagonal Line measured from the Centre.  
Note, That when the Rule stands at the Blunt Angle, it gives the longest Diagonal Line, and when it stands at the Sharp Angle, it gives the shortest Diagonal Line.  
5. By the Diagonal Line and Perpendicular to find the Hips Length, and the Angles at Head and Foot of the Hip or Sleeper.  
Count the half Diagonal on one Leg, and the Perpendicular 
Hips.  height on the other Leg, (the 30 Scales being square) than the Parallel distance between, shall be the length of the Hip required, being longer or shorter, as the Diagonal Line is.  
Also a Rule laid to the two Points of the Compasses measuring the Parallel Extent, and a Bevel laid to the Rule, and 
Angles of the Hips.  the two 30 Scales, at each end, gives the Angles at head and foot of Hips required.  
To find the Nearest Distance from the Corner of the Rombus to the Opposite Hippolito set up in his true place.  
6. Count the length of the Hip on one 30 Scale, and take that distance also between your Compasses Laterally, count also on the other 30 Scale the length of the Bevel end, and there set one point of the Compasses, and open or shut the 
Nearest Distance.  Rule, till the other point falls in the length of the Hip-Rafter first counted (then one 30 Scale Represents the Raising Piece, and the other the Hip set up) then the nearest distance from the breadth of the Frame over, at the Bevel end and more, or less, by half the Feet and Inches Bevelling, to the Common Line of the other 30 Scale, being measured from the Centre shall be the nearest distance required.  
To find the Angle on the Outside of the Hip.  
7. To find the Outside Angle of the longest Hip, Take the shortest Diagonal Line between your Compasses, and make it a Parallel in the nearest distance belonging to that Hip, and the 30 Scales will be set to the Angle required, and to measure it take Parallel 15 and 15, and measure it Laterally from the Centre in the Chords; and you shall have the measure 
Outside Angle.  of the Angle required.  
Example; In a House of 20 foot over at nearest distance, and 4 foot or 48 inches Bevelling out of Square. See fig. II.  
Let A B C D represent a Frame 20 foot over, and 4 foot Bevelling, the Bevel-end B C is longer than right over by 5 inches; for if you set the Rule square, and take the parallel extent from 20 the measure over, to 4 foot the measure of Bevelling, and measure it Laterally, you shall find it reach, Laterally to 20 foot and 5 inches, the true length of the Bevel end.  
The Bevel-end being 20. 5 inches the Perpendicular resolved on, which at true Pitch ought to be about 11 foot 5 inches, Fere. Then first for the Rafters length.  
1. Set the 30 Scales square, and set one Point in 11. 5 the Perpendicular, and the other point in 10 foot 2½ the half Bevel-end; (and to the Compass-Points, lay a Rule, and to the Rule and the 30 Scales at both ends set a Bevel, and one shall 
Rafters Length and Angles.  be the Angle at foot, the other the Angle at the top of the Rafter: And the one Angle will be 42 Degrees for the foot, and the other 48 for the top of the Rafters) and the measure between the Compasses measured from the Centre shall be 15 foot 4 inches, the Rafters length required.  
As by Inspection on the 40 and 30 Scales you may see.  
2. For the longest Hip set one Point in 12 foot 2 inches and ½ more by two foot, then 10 foot 2 in. ½ the half Bevel-end, and the other Point in 15. 4 the Rafters length, and measure it from the Centre, it gives 19 foot 6 inches the longest Hip.  
Again, Set one Point in 8 foot 2 inches ½ 2 foot shorter than the half Bevel-end, by 2 foot the half of 4 foot the Bevelling, 
Hips Length.  and the other Point in 15 foot the Rafters length, and measure it from the Centre, it gives 17 foot 4 inches the length of the shortest Hip.  
3. For the length of both Diagonal Lines, set the Scales of 30 to the Angle of the Frame at each corner, and the measure from the half, or the whole Bevel-end taken Parallelly, shall be the length required of the half or whole Diagonal Line, according as you take the whole or half Bevel-end.  
As here in our Example the Blunt end is 101 gr. 30 min. 
Diagonal Lines.  or 11 30 more than 90 gr. therefore take the distance from the Centre to 101. 30. on the Chords, and make it a Parallel in (15 and 15) the Chord of 60, then is the 30 Scales set to the Angle of the Blunt-end of the frame, and the Parallel distance between 20-5 the whole Bevel-end gives 31 foot 6 inches, the whole Diagonal Line, B L, or the Parallel between 10-2½ give 15-09 inches B E the half.  
Again, The sharp end is 78. 30 11 deg. 30 less than 90, than the Lateral Chord of 78. 30. made a Parallel Chord of 60 (at 15): then is the Rule set to the sharp end of the Frame, for the shorter Diagonal Line. And the Parallel distance between 10-2½ gives 12 foot 11. the half, or 25 foot 10 inches the whole Diagonal Line C F, whose half is C E the shortest whole and half Diagonal Lines.  
4. For the Hips Length, and Angles at Foot and Head.  
Set the 30 Scales Square, and count the shortest half Diagonal 12 foot 11 on one Leg, and the Perpendicular 11 foot 5 on the other Leg, than the Compass Points so set, lay a Rule 
Hips length.  and take the Bevel at both ends, and it shall give the two Angles at head and foot of the shortest Hip, and the same distance of the Compass Points shall be 17 foot 4 inches fere, the Hip 
Hips length and Angles.  length, as before, and the Angle at the top 48. 30 and at foot 41▪ 30 his Compliment.  
Again, Set one point in 15 foot 10 the longest half Diagonal, and the other point in 11 foot 5 inches the Perpendicular, and lay a Rule to them, and set the Bevel to both ends, and you shall find 54 gr. the Angle at the top, and 36 the Angle at foot, and the distance between the Compasses laid from the Centre, gives 19 foot 6 inches the longest Hip.  
5. For the Outside Angles of both Hips, the longest first.  
Take 19 6 between your Compasses the Hips length from the 30 Scale: Set one point in 20 foot 5 the Bevel-end, and close the Rule till the other Point touches 19 6 the Hips length.  
Then take the nearest distance from 18 foot 5 (2 foot less 
Outside Angle of long Hip.  than 20 foot 5 the breadth of the Bevel-end of the frame), to the other 30 Scale, and it is the nearest distance from the Point of the Rombus A to the Hip B G setup, 15 foot 9 inches.  
Then take out 25 foot 10 the shortest Diagonal, and make it a Parallel in 15. 9 the nearest distance, and then the 30 Scales are set to the Angle required; for the Outside of the Long Hippolito, being 110 degrees for Parallel 15 measured laterally on the Chord, gives 110-0.  
6. For the Outside Angle of the Shortest Hip.  
Take 17 foot 4 inches between your Compasses, and set one Point in 20 foot 5 the Bevel end, and open or shut the Rule till the other Point reaches 17 4 on the other 30 Scale. Then 
Outside Angle of short Hip.  the nearest distance from 22 foot, 2 foot more than the breadth of the Bevel end of the Frame to the Common Line on the other 30 Scale, and that shall be the nearest distance from L to C G the shortest Hip set up, which is 18 foot 9 inches.  
Then take out 15 foot 10 inches the half greater Diagonal Line, (because 31 foot 8 inches is more than the Scale of 30) and make it a Parallel in 9 00 the half of 18 foot, and the 30 Scales are set to the Angle required, viz. 122 degrees; for if you take out parallel 15, and measure it in the Chords Laterally, it shall be 122 the Angle required.  
Fig. III   

Use XVI.  
To find the Rafters, Hips and Angles in Bevel and Taper Frames, being broader at one End that the other. See Fig. III.  
First, when the Frame is broader at one end than the other, than the middle breadth is to be the guide for the Rafters length, and the Perpendicular to be equal to the middle Rafters perpendicular on both ends; though one pair of Rafters is longer than another, and the Roof in winding thereby: Which winding may many times be remedied by some convenient artifice or other, a, the ingenious workman will soon perceive. As thus in brief:  
Let A B C D represent the Frame of a House Bevelling at both ends, and broader by 2 foot at one end than the other; as here in the Bevelling figure, being 20 foot on one side, and 24 foot on the other side at one Bevel-end 10 foot 4 inches, and at the other end 8 foot 1 inch ½ but at the nearest distance over, only 10 foot, and 8 foot.  
First, for your more apparent fatisfaction, draw the true form of the Frame by as large a Scale as you conveniently can, with the Sides and Angles as exact as you can, as A B C D; then draw the middle Line E F quite through the length, and G H through the breadth of the Frame Perpendicular one to the other, than measure G H as suppose 9 foot, then lay off the half of G H from H to I and K, then take out ¾ of G H, and lay it from K and I to L 6 foot 9 inches for a pair of middling Rafters for this Taper House, L G being the common Perpendicular at the middle and both ends of the Roof, 5 foot o inch ⅝ of an inch.  
And for the Principal Rafters, or other Rafters open the 
To find the length of the very Principal (or single) Rafter in a Taper Frame.  30 Scale square, and then count the Perpendicular 5. 0. ⅝ on one Leg, and half the distance between the Rafter-feets or half breadth of the Frame at that place on the other Leg; and the Parallel distance between shall be the true length of the Rafter required.  
Then for the Hips length, first, Make A M and B M equal to A E or B E at one end, and make C N and D N equal to D F or C F and draw the lines M M and N N at both ends, also make A b and B b equal to A B, and C a and D a equal to C D, and draw the Diagonal Lines A S and B S, and C O, and D O, at each end extended, and set down the measures of them.  
These Lines being drawn you have the half Diagonal Lines A S and B S, and C O, and D O, and may measure them by your Scale, to find their Lengths, or set the Rule to the Angles A E S and B E S, find them by the 30 Scale; also you have the Bevel ends of the frame, and the nearest distance over from side to side of the frame.  
Then for the Hips Length and Angles thus,  
Set the 30 Scales square, and count the perpendicular height L G on one Leg 5- 0- ⅝ and each half Diagonal Line, etc. one after another on the other Leg, and the Parallel distance between shall be the true length of the several Hips required, Example,  
The Parallel distance between 5 foot- 0- Inches ⅝ the common perpendicular counted on one 30 Scale, and 8 foot 1 Inch, the longest Diagonal line A S counted on the other 30 Scale shall give 9 foot 6 Inches for the Length of one Hippolito A P Laterally.  
And the Parallel distance between 5- 0- ⅝ the common perpendicular, and 6 foot 6 Inches the other Diagonal line B S shall give the Lateral measure of 8 foot 3 Inches, the length of B P, the other Hip-rafter for the broadest end of the frame A B.  
Again, the parallel distance between 5- 0- ⅝ the common perpendicular, and 6 foot 4 Inches the greater Diagonal Line C O at the narrowest end shall give 8 foot 1 Inch for the Hip-Rafter C P. And the parallel distance between 5- 0- ⅝ the prependicular and 5 foot- 0- Inch.- 0 the Lesser Diagonal Line D O shall give 7 foot 2 Inches for the Hips Length D P to stand over the Diagonal Line D O.  
Note also that if to the Compass points standing parallelly you lay a Rule, and to the Rule (so laid) and the 30 Scales at each end a Bevel, and set it according to the Rule and 30 Scales, it shall give the true Angle of the Hips at the Raising-piece & King-Post, which 8 Angles in these 4 Hips are expressed by the Lines and Letters in the Scheam thus. P A S and P B S, P D O and P C O the 4 Angles at the Raising Piece. And S P A and S P B O P C and O P D, the 4 Angles at the King-Post.  
Whose length you may prove by Mr. Pope's excellent way, making S P and O P equal to L G on the extended Diagonal Line, and drawing the Lines A P, B P, C P, D P for the 4 Hip-Rafters length required.  
Or for more proof thus also by the Rule, as before in Square Roofs.  
Set the 30 Scales Square, and take the Parallel Extent, from 7 foot 2- ¾- the Rafters length at the broader end, on one 30 Scale, to 6 foot 2 inches more, than ½ the Bevel-end by 1 foot the half quantity of Bevelling, and it shall give 9 foot 6 inches for the Hip A P, and from 7- 2- ¾- to 4- 2, one foot less than the half Bevel-end, to 8 foot ¾ the Hip B P. Also the Par. Extent from 6 foot 5- ½ the Rafters length at the lesser end, to 5. foot 0- ¾ one foot more than 4. 0- ¾ the half little Bevel-end, shall give 8- 1- ½ for the Hip P C. And the Extent, from 6- 5- 4/8 the Rafters length, to 3- 0 ¾ 1 foot less than the half Bevel-end, gives 7- 1- ½ the Hip D P, as before.  
Note, That by the working these 3 ways, you may be sure to prevent any mistakes that may happen in working one way only.  
Lastly, For the Angles on the outside or backs of the Hips.  
Take every several Hips length Laterally between your Compasses, and set one Point in the length of the Bevel-end, (or rather in a mean between A B the Bevel-end, and M M at the greater end, or C D and N N at the lesser end) and open or shut the 30 Scales till the other Point falls on the Hips length that you work for, then for the longer Hip count more, and for the shorter Hip less, by half the inches Bevelling, than the whole breadth over, at the end, and take the Parallel nearest distance from thence to the 30 Scale for a nearest distance, which nearest distance you must keep.  
Then take the whole Diagonal Line Perpendicular to the Hip, wrought for (viz. the shortest Diagonal Line for the longest Hip at each end) between your Compasses, and make it a Parallel in the nearest distance last found, and then the 30 Scales are set to the Angle of the back of the Hip required.  
Example in this Figure for the longest Hip.  
Take 9 foot 6 inches, the Hips length A P between your Compasses, and set one Point in 10 foot one inch (a mean between A B 10 foot 4, and M M 9-10½) and open or shut the Rule, till the other point stands in 9 foot 6, the Hips length first taken. Then the nearest distance, from 9 foot 4 inches, one foot less than 10 f. 4 inc. the Bevel-end distance over, to the other 30 Scale shall give 7-10 a nearest distance from the Point b to A P the Hip raised over A S the Diagonal.  
Then the Lateral Extent B b of the whole Diagonal Line 12 f. 7 inc. being made a Parallel in 7-10 the nearest distance last found, shall set the 30 Scales to the Angle at R the back of the Hip required measured by taking Parallel 30, and measuring it Laterally on the Chords it is about 108 Degrees.  
Secondly, Take 8 foot 4 inches, the other Hips length between your Compasses, and setting one Point in 10 foot one inch as before, open or shalt the Rule till the other Point falls in 8. 4. the Hips length.  
Then the nearest distance from 11 foot 4 inches, one foot more than 10 foot 4 inches the distance of the Bevel-end to the Common Line of the other 30 Scale shall be when measured Laterally from the Centre 9 foot fere, for a nearest distance.  
Then 15 foot 8 inches the longer Diagonal Line being made a Parallel in 9 foot fere, the nearest distance last found, sets the 30 Scales to 121 Degrees the Angle required, the back of the shorter Hip required.  
The same work serves for the other end, being near the same Angles: Which you may prove by Mr. Will. Pope's excellent way thus: find the middle between S and A, or S and B at Q, than the nearest distance from Q to B P or A P near lay to R, and draw the Lines R E, R M for the Angles at R the back of the Hips required.  
Moreover if you raise 4 Perpendiculars cutting the Points O and S, the 2 places of the King-posts being Perpendicular to the raising Pieces A C, and B D, as the 4 Prick-lines ♉ S, ♍ S, ♌ O, and ♊ O do show, and lay the length of each Hip from his proper corner A B C D as A P from A to ♈ and ♍. B P from B to ♈ and ♉, D P from D to ♊ and ♋, C P from C to ♌ and ♋, then draw lines from point to point, as in the Figure.  
Then ♍ ♌ and ♉ ♊ are the two Ridges when turned right over O S, and C ♋ D is the least Hip, and A ♉ B is the greater Hip, as Mr. Pope hath well showed. Thus much for Hipt Roofs.   

Use XVII.  
To find the Length and Angles of every Principal Particular Rafter in Frames broader at one end than the other.  
The Perpendicular, as before was hinted, is to be the same all over the Roof. Therefore open the Rule square, and take from the Perpendicular on one Leg, to the half breadth of the Frame on the other Leg, measure it from the Centre, and that is the length required. For the Angles lay a Rule to the compass Points, and set a Bevel, as before is showed, and you have the Angles at the Raising-Piece, (and Ridge of the House), to cut the Rafters feet by.  
The same Rule serves to draw out a pair of well Stairs, to give Hypothenusaes', or strings, at any particular height and breadth; for the 30 Scales set Square, and the Perpendicular height counted on one Leg, and the breadth on the other Leg, the measure between is always the Hypothenusa, or string in flying Stairs, as may plainly appear.   

Use XVIII.  
To find the Length and Angles of Collar Beams in any Roof.  
Take the whole breadth of the Frame between your Compasses, and set one point in the length of the Rafter on one Leg, and the other point in the same place on the other Leg: then the two Legs represent the two Principal Rafters, and a Rule laid to the Compass Points represents the Raising piece; then at any height that you please above the Raising-piece, apply a Rule parallel to it, and the measure between laid from the centre, gives the length, (remembering to add wood for the tenons) and a Bevel laid to the 30 Scale and Rule, gives the true Angle to cut it by, (where the Timbers be square.)   

Use XIX.  
To find the Lengths, and Angles, of Rafters, and purloins in Bevel Frames.  
The Length of the Rafters is showed before, to find it by the half breadth of the Square or Bevel-end, and the perpendicular answerable to that Roof, (as afterward in the Example.) And the Angle of the Foot, and outsides or backs of the Bevel-end Rafters, and the upright of the Gable end, must be to an Angle less and more than 90 degrees by the Angle at the Corner of the frame where that Rafter is to stand, being more at the sharp Angle and less at the blunt Angle, as in figure IIII you may see; the true quantity of which Angle is thus found by the Rule.  
Take the Length of the Rafter for the Bevel-end in Feet and Inches, and make it a parallel in 15, then half the quantity of Feet and Inches Bevelling, taken from the same Scale and carried parallelly till it stay in like parts, shall show right against it in the Tangents the Degrees and minutes required.  
And this is the Angle that the blunt corner is to be laid in Legement more than a square, and the sharp Angle less than a square or 90 degrees, both out of Level, and out of square also, when you tumble or stripe in, the tenons of the purloins, the thing desired.  
Fig. III  
Let A B represent the Bevel-end of a frame, being out of square from the Line A C 6 Foot as the line C B showeth, then if A C be 20 foot, A B will be 20 foot 10 Inches. Then draw E L the middle Line of the frame, and G M and H K, the Lines at three quarter of the breadth of the frame, then take E D the half Bevel and lay it from G to F and from H to I, and draw the Line; A F and B I, for the outside Lines of the two Bevel-end Rafters: and the two other Lines parallel to them, according to the breadth or scantling of your Bevel-end Rafters, as here in the figure 8 Inches broad. Thus the Lines A F, and B I, represent the two end Rafters, laid in Legement to fit in the purloins, as for their lying out of square from the Raising pieces. And to the same Angle they are to be laid out at Level, that the cutting of the purloin ends may fit the Rafter sides, when erected in their places, according as the ends F and I of the Bevel-end Rafters are, according to the Angles A F G and A F M the one being 11 degrees and 20 minutes under, and the other 11, 20 above 90 degrees.  
Also, Note that if P K, and O M do represent a pair of square Rafters, at any intended distance from A, then T S and R Q will give the true Length of the purloins fit for those places, R Q being the shortest purloin and T S the longest purloin.  
To find by the Rule only how long the purloin must be on the outside more or less than the distance on the Raising pieces, where you intent the two square Rafter feet shall stand, do thus: set the 30 Scales to the same Angle that the Bevel-end Rafters lie out of square, when they lie in Legement, to frame which here is to 11 degrees and 20 minutes.  
Then count from the Centre the quantity of Feet and Inches you intent to make the mortise holes from the Rafter foot, in the Rafters, for the tenons of your purloins; and take from thence to the nearest distance to the other Line, and that shall show the quantity that the one purloin is to be longer, and the other shorter, than the distance between the Rafter-feets on the Raising pieces, Example thus,  
Set the 30 Scales to the Angle G A F, then count A S the place for the mortise hole from A on the Rafter, and take the nearest distance from thence to the other 30 Scale that shall give S V, the quantity how much T S is shorter than A O, and how much R Q is longer th●n P B.  
Note, that if you count 3 quarters of 20 foot 10 Inches, being the length of the Bevel-end, that then you will make the Rafters too long by 4 Inches and a half, as in the figure you may see: therefore the surest way to find the Rafters length is to set the Scales to a square, and then to take the parallel extent from the common perpendicular, to the ½ breadth between the place for the Rafter feet, on the Raising piece: So that the length of the Rafters for the Bevel-end at true pitch, is A F 15 foot 3 Inches, and not A W 15-7-½, which is just 3 quarters of A B the Bevel-end over which the two Rafters are to stand. For then the top of the Bevel-end Rafters would be too high for the top of the square Rafters being cut Just 15 foot, three quarters of 20 foot the breadth of the frame.   

Use XX.  
The use of the Scales to lay down or measure out on Paper, or Board, the Members and parts of the fine Columns, and their Ornaments, with their names and measures, digested into a Table, for the more ease and use of workmen.  
For the drawing of the fine Columns and their Ornaments is largely before treated of in the former part, by models minutes and quarters, and considering the harmony between it and our Scales to 30, that are parted into 12 parts, so that when every figure or foot, on the Scales to 30 represent a model, than every Inch is 5 Minutes; and for small paper draughts, that way of counting is near enough, but when you use it for a bigger draught, that the whole scale of 30 may represent 3 models only: then every figure will represent 6 minutes, and the 12 Inches between are half minutes: but in very great work as in Temples, or Castles, than the whole foot or scale to 30 may represent half of one model only, and then every figure or foot is a minute, and every Inch or small division is the 12th part of a minute; for I count it to be a large Column, whose Diameter at the base (which is a model) is above 3 foot, and by this manner of computation which is natural to most scales, the scales to 30 may be rendered convenient for small, or moderate, or large uses, as in the following Examples may somewhat appear,  
In Reading of which you must have recourse to the former figures whose members are marked with 1 2 3 4 5 6 7 8 9 10 and which figures direct you to the names in every of the columns which I found to be wanting in the former part, so that the method here used is thus,  
1. The first Column in the Table is 1 2 3 4 5 6 7 8 10 11 12, etc. answerable to the figures on the 6th figure, in our present Example, which will straight way guide you to the meaning of the names or terms in the Table by comparing it and the figure together, whereby you may readily find every part or member and its proper name.  
2. The second Column is the names of the part or Member in the gross and particular also, as the Pedistal, the Base, the Shaft, the Capital, the Architrave Frieze and the Cornish, are the names in gross; the other are the names of the members in particular.  
3. The third Column in the table is the several measures of the particular members, in Models, Minutes, and quarters, as in the figures, though more easily to be seen than in the figures, because of the straightness of the Room there,  
4. The fourth Column in the Table is the measure of every particular part and member from the pedistal base or bottom to the top of the Cornish, being useful in small draughts where the whole pillar is expressed.  
5. The fifth Column in the Table is the several measures of every particular member of each gross part, being useful when you draw large draughts of any work or part thereof.  
6. The sixth Column in the Table is the measure of the projecture of every particular part from the middle line of the Column (or from the smallest or most inward part of the pillar the rest being substracted) but I Judge the middle line to be the best Epocha to begin the account of projecture for the conveniency of the Compasses: and this Table of projectures as all the rest is to models minutes and quarters; as by trial you may see at one view what each gross part and every particular part is.    

The Names and Number of the Members of the Tuscan Column in Height and Projecture.  
  A Table for the Tuscan Order Each part from the base Each gros part alone ●he proj. ●r. middle. Num.  Names of the parts and members. nod. min. q. M. m. q M. m. q. M. m. q. 1 Pedistal. The lower Face●, or Plint, of the Pedistal 0 30 0 0 30 0 0 30 0 0 42 0 2 The Pedistal Body, or Stilobatum 1 0 0 1 30 0 1 30 0 0 40 0 3 Abacus, the Casement, or hollow 0 5 2 2 35 2 1 35 2 0 41 0 4 Tinea, the List, or Square, or Rabbit 0 1 2 1 37 0 1 37 0 0 46 0 5 The Architrave or Faceo 0 12 0 1 49 6 1 49 0 0 47 0 6 The upper List of the Pedistal. 0 3 2 1 52 2 2 52 0 0 49 1 7 Base. The Plint, of the Base of the Column 0 18 ● 2 10 2 0 18 0 0 42  8 The Thorus, or Rondell, or Breast 0 12 0 2 22 2 0 30 0 0 42  9 The List, or Fillet, or Spira 0 03 0 2 25 2 0 33 0 0 36   Shaft.  at the Base          0 30 0 10 The Shaft or Body of a Col.  6 22 0 8 47 2 6 22 0      at the Capit.          0 22 2 11 Cap●ital. The List 0 1 2 8 49  0 1 2 0 24  12 The Rondel or Astragal 0 3 2 8 52  0 5 0 0 26  13 The Neck or Freeze 0 8 2 9 01 0 0 13 2 0 22 2 14 The List 0 1 2 9 2 2 0 15 0 0 24  15 The Rondell, or Bead-molding 0 2 2 9 5 0 0 17 2 0 26  16 The Echinus, or Half-round 0 7 2 9 12 2 0 25 0 0 30  17 The Plint of the Captital. 0 10 0 9 22 2 0 35 0 0 31 2 18 Architrave, Freeze and Cornish. The first Faceo 0 10 0 9 32 2 0 10 0  22 2 19 The second Faceo 0 15 2 9 48 0 0 25 2  24 2 20 The List or Supercilium 0 1 2 9 49 2 0 27 0  26 2 21 The P●int 0 3 2 9 53  0 30 2  27 2 22 The Zoporus Epistylum or Freeze 0 40 0 10 33 0 1 10 2  22 2 23 The List or Supercilium 0 2 0 10 35 0 1 12 2  23 2 24 The Scimatium or little O G 0 5 0 10 40 0 1 17 2  26 2 25 The Supercilium or List 0 1 1 10 41 1 1 18 3  30 0 26 The Scima or Greater O G 0 8 2 10 49 3 1 27 1  35  27 The List 0 1 2 10 51 1 1 28 3  49 0 28 The Corona or Crown 0 9 3 11 01 0 1 38 2  50  29 The List 0 1 2 11 2 2 1 40 0  52  30 The upper Scim● or O G 0 8 0 11 10 2 1 48 0  56  31 The Supercilium, List, Tinea, or Eyebrow 0 1 0 11 12 0 1 49 2 1 00 0 32 The upper List or P●int of the Cornish for the Tuscan Column or Order 0 3 0 11 15 0 1 52 0 1 02 0  
Thus I have given you an Example of the Tuscan Order of the Measure of every Part and Member: the like may you make, from the Figures in the Book, of all the other Orders, for your particular use and occasion.  
FINIS.   

The said Rule with all other Mathematical Instruments are made and sold by John Brown, living in the Minories at the Sign of the Sundial, and by Walter Henshaw in East-Smithfield near the Hermitage.  
There is also to be sold by William Fisher at the Postern at Tower Hill, a very useful Book, Entitled, The Description and Use of the Carpenter's Rule, together with the Use of the Line of Numbers, commonly called Mr. Gunter's Line. Also the Book of The Five Columns of Architecture by Hanc Bloom●.