#f FSACTICAL \i i sumwmm g'vi'y i J } ;;y::: ^LIBRARY OF CONGRESS.^ f [SMITHSONIAN DEPOSIT.] ' ? UNITED STATES OF AMERICA.! THE PRACTICAL SURVEYOR'S GUIDE, THE NECESSARY INFORMATION TO MAKE ANY PERSON OF COMMON CAPACITY, A FDaSHED LAND SIJRYEYOE, WITHOUT THE AID OF A TEACHER. BY ANDREW DUNCAN, LAND SURVEYOR AND CIVIL ENGINEEB. iDl PHILADELPHIA: HENRY CAREY BAIRD, (successor to e. l. caret.) LONDON: LOW, SON & CO. 1854. Entered, according to act of Congress, in the year 1854, by HBNRY^CARET BAIRD, In the Clerk's OfiSce of the District Court of the United States, for the Eastern District of Pennsylvania. STEBEOTYPED BY SLOTE & MOONEY, Philadelphia. ^^p s-s-siso ADYEETISEMENT. The intention of the Author of the following synopsis is to furnish a cheap, small book contain- ing the best practical information hitherto pub- lished and scattered through many eminent authors, nearly all of which he has carefully studied, and having had more than thirty years' experience as a Surveyor, &c., has often had occasion to carry large works in order to have at hand the things necessary in the immediate field practice of sur- veying, levelling, profiling, calculating excava- tions, embankments, &c. To render the book as cheap as possible, the tables shall be only those that are really wanted, but- by which all things in common practice can be readily done, viz : Lati- tude and departure, for four pole chains. A table of natural sines, cosines, and tangents, which are most useful for finding the radius of curves, degree of curvature, &c., on railroad and other curves, their application in finding grades, cuttings, fil- lings, &c., will, it is hoped, prove useful. (iii) iv Advertisement. Geometrical demonstrations are avoided, except in a few cases, the design of the writer being to furnish a short treatise, to direct at once to what is required. The work will be comprised in four divisons : 1st. The arithmetical calculation of plane figures. 2nd. The calculation of surveys taken with the compass and chain by latitude and departure, with various methods of proof. 3d. The method of plotting, enlarging and di- minishing maps, with remarks on copying and embellishing. 4th. Levelling, profiling and calculating cuttings and embankments, the use and application of the tables, together with many other useful things applicable in practice. PREFACE. The following compilation is made in consequence of the undersigned not having met with any work on Surveying sufficiently concise, and instructive in the several details, necessary to qualify properly the practical surveyor. Many of the works already published contain subjects not neces- sary in such treatises ; such as Geometry, Plane Trigo- nometry, &c., which subjects, it is taken for granted, all who intend to become proficients have studied prior to reading Surveying. They are also found not to contain instruction that in recent improvements the surveyor re- quires to know. Many of these things the compiler of this short treatise, will endeavour to supply ; also, many other necessary things, which, in his long experience, he has found indispensable to the correct practitioner. He has collected the most necessary insti-uction in leveling and profiling, with a new and speedy plan of setting grades on rail and plank roads. The method of inflecting curves, not hitherto sufficiently explained. The description and design of a new instrument whereby distances are found at once without any calculation, A new method of sur- veying any tract of land by measuring one line through it, with a geometrical demonstration of the same. A geo- metrical method of correcting surveys taken with the Com- 1* (v) vi Preface. pass, to fit them for calculation, with a table of corrections for certain distances, but applicable to all. A short method of finding the angles from the courses, and vice versa. The method of surveying with the Compass through any mine or iron works, and to correct the deflections of the needle by attraction. Description of an instrument by the help of which any gentleman may measure a map by inspec- tion, without calculation. A new and short method of calcu- lation, wherein fewer figures are used than in the common method ; also, the Pennsylvania method. Tables of diff'er- ence ■ of Latitude and Departure, made expressly for two pole chains, but which can also be used with four poles. The method of correcting the diurnal variation of the needle, most useful in tracing the boundaries of surveys, a complete description of which is given with the reason for using 57-3° and how it is found. Various methods of plotting and embellishing maps. The most correct method of laying ofi" lots with a pole, plummets, &c. Description of a new Compass which the compiler has contrived for that purpose, and which is made by Reid & Sons, Smith- field street, Pittsburgh. The compiler does not deny that he has borrowed from many authors those things he has found best adapted to the completion of a work adequate to make a finished American Surveyor, of which an unprejudiced and en- lightened public are the best judges. ANDREW DUNCAN, Land Surveyor and Civil Engineer, Office, Odeon Building, Fourth St., Pittsburgh, PRACTICAL SUEYEYOE'S GUIDE. Problem First. To reduce two pole chains and links to four pole ones. If the number of chains be even, the half of them will be four pole ones, to which annex the given links. Thus : 1. In 16 chains, 37 links of two pole chains how many four pole ones : 2)16. 37 Ans. 8.37 But if the number of chains be odd, take half of them and add 50 to the links. Thus : 2)131.40 Ans. 65.90 Problem Second. To reduce four pole chains and links to two pole ones. Double the chains and annex the links if (9) 10 The Surveyor's Guide. they be less than 50, but if they exceed 50, add one to double the chains and take 50 from the links. C, L. Thus : 16. 25 of four poles, how many two pole chains. 16.25 . 2 Ans. ^32.25 C. L. 2d. In 19.87 four pole chains how many two pole ones. : 19.87 2.50 Ans. 39.37 To reduce two pole chains and links to perches and decimal of a perch, multiply the chains by C. L. two and the links by four, thus: In 16.37 how many perches. 16.37 2. 4 Ans. 33.48 Article First — of Areas. A square is a plane figure having four equal sides and four right angles. To find the contentj The Surveyor's Gtuide. 11 multiply the side into itself aB;d the product is the content. Example. Required the area of the square A B C D, one of whose sides is 25 chains 95 links. Fig. 1. 25.95 25.95 12975 23355 12975 5190 A A. K. P. 67. 1. 14.44 A. 67.34025 4 C 25.95 R. 1.36100 40 P. 14,44000 A parallelogram is a four sided figure whose opposite sides and angles are equal. To find the area multiply one of the sides by the p.erpendicular demitted from one of its opposite, angles. Example. Required the area of the parallelogram A B 12 The Surveyor's Guide. C D, the length of which is 15 chains, and height C. L. 12 64. Fig. 2 12.64 A. R. p. 18.3. 33.6 D 15 00 ( 12.64 15 6320 1264 Acres, 18,960 Roods, 3.840 40 Perches, 38,600 The content of an oblong piece of ground and one side are frequently given to find the other. Divide the area in perches by the given side, gives the side required which is easily reduced into chains and links. If a lot contains 507 perches and is 14.25 long, what is its width. The Surveyor's Guide. 13 29)507 '17.4827 29 .25+12.06=8 37.06 217.0000 203 140 116 240 232 80 58 220 203 To draw maps of these figures is too obvious to require any explanation. 5th. When the sides of the above figures are given in feet and inches, reduce the inches to deci- mal of a foot. Then multiply the length by the breadth and divide the product by 43560, the number of feet in an acre, the quotient will be the acres and decimal of an acre, which may be redu- ced to roods and perches by multiplying by 4 for the roods and 40 for the perches, pointing off the proper number of decimal places each time, thus : A lot of land is 600 feet 4 inches long and 240 2 14 The Surveyor's Guide. feet 3 inches wide, how many acres does it contain. 600.333.X240.25=144230.00325 This divided by 43560. gives 3.31106 or 3 1 0^9.76 4 1.24424 40 9.76960 Ans. 6th. A trapezium is a four sided figure the oppo- site sides of which are neither equal nor parallel. To find the content, measure a diagonal and two perpendiculars to the opposite corners, multiply the diagonal by half the sum of the perpendicu- lars, and the product will be the area. Example. Let A B C D be any trapezium, having A C 80 perches, and the perpendiculars as in the figure. The Surveyor's Guide. 15 25 20 2)45 22.5 80 160)1800,0(li.l.00 Ans. 160 200 160 40)40(1 40 7th. A triangle is a figure having three sides and three angles, any side may be called the base, having the base and perpendicular given. Multi- ply the base by half the perpendicular, or the base by the whole of the perpendicular, and take half the sum. Example. LetABCbeany triangle whose base is 100 two pole ch's and 15 links, and perpendicular 40 16 The Surveyor's Guide. chains and 20 links, required the content in acres. 100 15 2 4 40 20 200.6 perches and decimal. 2 4 40.4 half the perpendicular. 2)80 8 8024 8024 40 4 A. R. P. 160)8104.24(50 2 24.24 Ans. 800 40)104 80 24 8th. Having the three sides given to find the area rule, add the three sides together and take half the sum, from which subtract each side severally, multiply the half sum and three remainders con- tinually into each other, and the square root of the product will be the area. The most satisfactory proof of the above rule is the following : Let A B C be any triangle, B C its base, A B the greatest side, and A C the least, and let P be half The Surveyor's Guide. 17 the perimeter. In A B take A D=A C, join D C and draw A E perpendicular to D C and E G pa- allel to B C cutting A B in G, with tlie centre G and radius G E describe a circle cutting A B in L and A B and E G pro- duced in K and H. Join H B and produce A E, Kg. 5. H B till they meet in M. Since A D=A C and the angles at E are right, the squares of A E, E D are equal 2 A E,+2 E and .-. E D=E C or D 0=2 D E. Hence by similar triangles D G E, D B 0, B 0=2 G E=E H, and B is also paral- lel to E H .-. H B M is parallel to E D and (Euc. 1st 29th) the angle B M E=D E A, viz : a right angle, and H E being a diameter, M is a point in the circle. But from similar triangles D G E, D B 0, D B=2 D G, to each of these equals add A D+A 0=2 A D, and B A+A 0=2 A G, to each of which equals add B 0=2 G E=2 G K .-. A B+A 0+B 0=2 A K or A K is =P, half the perimeter. Now the area of the triangle A B 0=area A D 0+area B D 0=A EXD E+ 18 The Sueveyor's Guide. M EXD E (B M being parallel to D C)=A MXD E. But by similar triangles A D E, A M B : A E : E D :: A M to M B, and by equi-multiples the first multiplied by third : the second multiplied by the third :: the second X by the third : the second X by the fourth. Hence, A EXA M : E DXA M :: E DXA M : E DXM B, i. e. the area of the triangle is a mean proportional between A EXA M, and E DXM B. Now E DXM B = P— A BXP— A C, and A EXA M=A LXA K= PXP — B 0. Hence the area of the triangle is : ^fPXP— A BXP— A GXP— B 0, which is the rule. Example. 9th. Suppose the sides to be measur- ed by a four pole chain and be AB 10.64) A C 12. 28 y BO 9. 00 J Sum 31.92 I sum 15. 96 5. 32 first remainder. 3. 68 second do. 6. 96 third do. Fig. 6 The Surveyor's Guide. 19 15.96X5.32X3.68X6.96=2174.71013216(46.6337 16 A. R. 4 2 616 926)5871 5556 And since 10 square 4 pole ch's make one acre, this becomes 9323)31501 27969 93263)353232 279789 932667)7344316 4.66337 6528669 4 p. 26. 2.65348 40 The content is 26,13920 If the sides are in perches and decimal, divide the square root of the products of the half sum and three remainders by 160, and the quotient will be the acres, and the remainder divided by 40 will be the roods. The same may be more readily done by loga- rithms, for as the addition of logarithms serves for 20 The Surveyor's Guide. the multiplication of their corresponding numbers, and that the number answering to the half of a lo- garithm will give the square root of the number of that logarithm, it follows that half the sum of the logarithms of half the sum of the sides, and the three remainders will give the area, thus : Half sum, 15.96 log. 1.20303 First remainder, 5.32 Second " 3.68 Third « 6.96 " 0.72591 " 0.56585 " 0.84261 2)3.33740 Square four poles 46.63 Or, 4.663 4 1.66870 2.652 40 26.080 4 2 26 as before. 10th. When the three sides are given and the angles are required, call either side on which the perpendicular will fall from the o^pposite angle the base, then as the base is to the sum of the other two sides so is the difference of those sides to the difference of the segments made by the perpen- dicular, then half that difference added to half the The Surveyor's Guide. 21 Bum gives the greater, and substracted the less, by •which means it is divided into two right angled triangles, the hypothenuse and one leg of each being given, the angles are easily found by plane trigonometry. Example. Let A B C be ^ \ Kg. 7 any triangle hav- ing the sides giv- en as follows,viz : A B 88, B C 54 and A C 108 to find the angles. A B=88 Then as 108 : 142 :: 34 B C=54 34 142 sum 34 difference. 568 426 108)4828.000(44.703 diff. of the 432 segments at the base. 22.351 half diff. 508 432 760 756 400 324 22 The Surveyor's Guide. Then half the base 54+22.351=76.351, the greater segment A B, and 54—22.351=31.649 the less segment. The triangle is now divided into two right angled triangles, the hypothenuse and base in each being given to find the angles, as follows : AsAB 88 1.9444827 : Rad. 90° 10.0000000 :: A D 76.351 1.8828147 11.8828147 1.9444827 : Sine A B D 60°.ll' 9.9383320 And 90— 60°.11'=29°.49'=-Angle BAD. In the same way C B D is found to be 35°. 53' its com- plement 54°.07'=/' B CD. Now A B D=60°.ll' C B D=35 .53 Angle A B C= =96 .04 t A= 29 .49 L C- 54 .07 180 .00 Proof as the three angles of every plane triangle are equal to 180° per 32d of the 1st of Euclid. lltli. Many things occur to the practical sur- The Surveyor's Guide. 23 veyor in the triangle, some of which I shall take notice of in this place. It often happens in prac- tice that the two sides and their included angle are given to find the other angles and side. Rule. — As the sum of the sides is to their differ- ence so is the tangent of half the sum of the oppo- site angles to the tangent of half the difference ; this half difference added to half the sum of the angles at the base gives the greater, and sub- tracted the less. Then aa sine of either of the base angles is to its opposite side, so is sine of the contained angle to the required side. Example. Let AC =80, B G =110,and /^ ACB 102°.30'to find A B c and the angles A and B. Side B C 110 From 180 Side AC 80 take /: C= 102.30 Sum 190 2)77.30 sum of base angles. Diff. of sides 30 | sum -38.45 24 The Surveyor's Guide. Then as 190 log. 2.2787536 88°.45' : 30 " 1.4771213 7 .13 :: Tag't 38°.45' 9.9044910 45 .58 U A 11.3816123 — 2.2787536 31 .32 B ::Tag'tofidiff.7°.13' 9.1028587 Then as sine B 31°.32' : AC 80 :: sine C 102.30 Or its supplem't 77.30 9.7184971 1.9030900 9.9895815 11.8926715 9.7184971 To A B 149.34 2.1741744 12th. Again, it often happens that the area must be found from the foregoing data, in that case multiply the two sides together, and that pro- duct by the natural sine of \ the contained angle, gives the area. Example. Let ABC be a triangle having the side A C 13 chains, A B 4. 7c. 501. and /- B A C 42° to find the area. The Surveyor's Guide. 25 7.5 13 225 75 97.5X.334565 half the nat'l sine of 42°= A. R. P. 32.62 square four pole chains = 32 19.2 Ans. Demonstration. Let fall the perpendicular B. D. A B : B D :: rad : sine A .-. B D=ABXsine^A Rad But rad.=l. .*. B D=A B=sine. Multiply each side by ACandBD. AC=AB. Sine A.XA C But A C. B D— the area. Hence, A B. A C. Sine A=area, which is the rule. 13th. Let B A C be a triangular farm, and P a well of water. It is required to draw a line or fence from the well that will divide the farm equally between two partners; 26 The Surveyor's Guide. Fig. 10. E D Find D the middle of the base, B C, and from P take a course of P D. Again set your instrument at A, and take the same course A E ; cause a pole to be set at E, a line or fence from E to P will bisect the farm, which is easily demonstrated from the figure. See Bland. 14th. Again, suppose the well P, to be situated within the farm, and it be required to divide it equally between three occupants, so that each may have the use of the well. a In fig. 11 di- vide the base B C, into three equal parts in D and E. Set your instrument at P, and take ^ Fig. 11. The Suevetor's Guide. 27 the courses P D and P E. Remove your instru- ment to A, and take A F the same course as P D, and A G the same as P E. Cause stakes to be driven at F and E in a straight line between B and C. Fences from F, G, and A, to P, trisect the farm, ■which is plain from the figure. 15th. To find the area of a Trapezoid Rule, multiply half the sum of the parallel sides by the perpendicular distance between them, and the pro- duct is the area. Let figure 12 be a Trapezoid ; if A D be q ..-,- bisected in E, and E F drawn parallel to A B or C D, it also j Kg. 12. bisects B C in F. — Through F draw ^G H parallel to A D. It is evident the triangles, B F G, and F C H, are similar and equal. (26th Euclid, 1st.) .-. E F, half the sum of the sides, multiplied by the per- pendicular distance between them, A B, gives the area. 28 The Surveyor's Guide. Being surveying on the side of a bog, and want- ing four acres to make up a division, and seeing A A 50 , C B would pass through a pond, I found A C fifty chains, and L C 56*^; how far must I measure from C towards B, so that the triangle ABC, may contain four acres. Since A C X C B X i the natl. sine of 56°=4 acres, it follows that 4 acres divided by the pro- duct of one half the natl. sine of 56° into A C, gives B C the required side. Thus : 50X4=200 perches X, 4145188=82.9 ; and 640 perches in 4 acres, divided by 82.9=7.72 per the length of B C, and in like manner any other simi- lar case can be done. 17th. Sometimes it is found necessary to ob- tain the area of a trapezium from having the diagonals and the angle of intersection given. The Surveyor's Guide. 29 Rule — Half the product of the diagonals multi- plied by the natural sine of the angle of intersec- tion, will be the area. Example. If the two diagonals of a trapezium be 40.15, and 60.13 chains the /- of intersection 75° 45', what is the area. J of 40.15X60.13=1207.1097= half the product of the diagonals, and 1207.1097X 96923=(natural sine of 75°45')=1169.966934531== A. R. P. the area, in square four pole chains, or 116. 3. 39. 47. Answer. 18th. To find the area of a trapezium, when each side and the angle of intersection of the diagonals are given. Rule — Square each side of the trapezium ; add together the squares of each pair of opposite sides ; subtract the less from the greater; multiply the diflference by the tangents of the angle of intersection. One fourth of the product will be the area. Example. What is the area of a trapezium, the sides of which are 10, 13, 7.16, 8.32, and 10.05 chains respectively, and the V of intersection of the diagonals 52° 15'. 30 The Surveyor's Guide. (10.13)=102.6169 ( 8.32)= 69.2224 171.8393=Sum of sqs. of opposite sides. (15.05)=226.5025 ( 7.16)= 51.2656 277.7681=Suni of sqs. of other sides. 105.9288 Difference, Multiplied by .32288=1 the natural tangent, 34.20290944 or A 3. 1 .27,23 perches. For a demonstration of the foregoing, see Cfib- son's Surveying, hj Trotter. 19th. To find the area of a trapezium, when the four sides are severally given, and also the sum of any two opposite angles. B,ule — From half the sum of the four given sides, subtract each seve- rally ; multiply the four remainders continually together ; from the result subtract one half the continual product of the four sides, multiplied by unity, increased by the natural cosine of the sum of the given angles. The square root of the result will be the area. The Surveyor's Guide. 31 Remark. In the application of this theorem, it must be carefully remembered that the cosine of an angle ' is positive when that angle is in either the first or fourth quadrants, and negative when it is in the second or third quadrants. For a demonstration of this beautiful theorem, see also, Grihson, hy Trotter. N. B. When the sum of the opposite angles is 180°, that is, when the trapezium can be inscribed in a circle, the above rule is simply : frop half the sum of the given sides, subtract each side seve- rally ; multiply the four remainders continually together, and extract the square root, gives the area. Example. " One morning in May I went to survey, As soon as bright Sol I espied ; I measured round a four cornered ground. In the margin see the length of each side ; The angle at B, together with D, An hundred and fifty degrees ; The meadow's content is all that I want, Assist me kind youths, if you please." 32 The Surveyor's Guide. A B 15.60 B C 13.20 C D 10.00 D A 26.00 ch'ns. 2)64.80 sum. 32.4=J sum. rig. 14. 16.80=lst remr. S=half the sum. 19.20=2d do. of the sides. 22.40=3d do. 6.40=4th do. Whence (s-A B)X(s-B C)X(s-C D)X(s-D A)= 32.4X16.8X19.2X22.4X6.4-46242.2016=46242. 2016 And A B. B C. C D. D A.X(l+cos. 150°) That is 15.60X13.20X10.00X26.00 -X0.1339746=3586.4464 Difference=42655.7552 The square root of 42655.7552 is 206, 5327= A. R. P. area in square four pole chains, or 20. 2. 24,55232. N. B. This problem is taken from Deighan's Arithmetic, vol. second, page 148, and the answer A. K. p. there given is 21. 2. 00,64, which is obtained by taking the trapezium to be inscribed in a circle, which is not the case. The Surveyor's Guide. 33 When the opposite angles of a quadralateral are equal to two right angles, a circle can be described about it. The rule to find the area, then, is : mul- tiply the half sum, and four remainders continually together, and extract the square root, for in that case l+cos.(A+B)=0. 21st. To find the area of a circle having the diameter given. Rule — Square the diameter, and multiply by .7854, and you have the area. 22d. To find the area of an ellipsis. Rule — Multiply the transverse and conjugate diameters together, and that product by .7854, and you have the area. 28d. To find the area of a parabola. Rule — Multiply the height by the breadth, and take two- thirds of the product ; you have the area. 24th. To find the area of a segment of a para- bola. Rule — Multiply the base of the segment by the altitude thereof, and two-thirds of the product gives the area. 25th. To find the area of a field or lot, which is found to be the frustum or zone of a parabola, included by two parallel right lines, and the inter- cepted curves of the parabola. Rule — Add the two 34 The Sukveyor's Guide, parallel ends, divide the square of either of these ends by this sum, add the quotient to the other end, multiply this sum by the altitude of the frus- tum or distance of the ends, take two-thirds of the product, and it gives the area. TRIGONOMETEICAL SURVEYING. 26th. It was not my intention to say any thing concerning this branch of surveying, as it is too extensive a subject for this small work ; but as some young readers may not have met with any thing on that subject, I will present them with an outline of how that grand operation is conducted. When an entire country, or part of a country, containing one or more counties is to be surveyed, it is done by triangulation, and the application of the rule given in the 12th section of this work. A line of some miles in length is measured and re- measured in order to prove its accuracy, on some plane or heath which is nearly level, first having been traced by a transit instrument, and poles placed in an exact straight line, to guide the meas- urers, as A B in the annexed figure, which is assu- med as the base of the operations. A number of hills and elevated spots are selected, on which sig- nals can be placed, suitably distant and visible (35) 36 The Surveyor's Guide. one from another. Thus, ifACDEBHG F, &c., be several objects, the situations of which D Fig. 15. are to be laid down on a map, and they are within the lines, ACDEBHGF, accu- rately calculated. It is supposed that the stations A and B are chosen such as that all the others can be seen from each of them. Then from the ex- tremity A, measure the angles E A B, D A B, CAB, &c., H A B, G A B, F A B, &c. And from the other extremity B, measure the angles, CBA,DBA,EBA, &c.,FBA, GBA,HBA, &c. And as the common base, A B, and the seve- ral angles of all the triangles are now known, the sides, A C, A D, A E, &c. may be determined by simple proportion, for as the natural sine of The Surveyor's Guide. 37 A C B : A B : : sine C A B : C B and so is sine ABC to C A, and so through all the triangles, the three sides being thus found in each triangle, the area is easily found, as shown in section 8th of this trea- tise. But to insure accuracy the objects C D E, etc., should be all intersected from some third station, O in the base A B, otherwise the figure may ap- pear in the plotting to be right when it is not so, and there will be no means of knowing whether the angles have been correctly taken without going over the work again. 27th. Here follows an example of a triangle con- A. R. p. taining a mean area of 1135.2.12.79. The] sides of which were traced by a transit instrument, and poles placed at the several points marked thus O ; this being done, the respective distances of the sides were ascertained by a mean of measures as follows, viz : B A 14643 links, or 9664.38 feet, A C 17814 links, or 11777.24 feet, B C 16588 links, or 10948. 08 feet. The angles were taken by a theodolite as they are marked in the figure. Now to determine the area of the triangle, A BC: 38 The Surveyor's Guide. 50°.1S'.21', Fig.IO. /'^^ 14643 Unks, or 9664.38 feet. 1st. From the data, A B, and the three angles of the known formula A B^Xsine BXsine A, a r p' =1135.2.27.18 2 sine C. 2d, by B C, and the three angles, the area will be 1135.3.029 3d, by C A, and the three angles, the area will be 1135.0.38.6 The Surveyor's Guide. 39 4th, by data A B, and the two adjacent angles, we have by the known formula, A B^Xsine BXsine A, 2 sine (B+A) The area will be 1135.2.25.7 5th, and by B C, and the two ad- jacent angles 1135.3.01.9 6th, by a similar formula from A C, and the two adjacent angles, the area will be 1135.0.37.99 7th, by data A B, and the adja- cent angle A, and the remote an- gle C, we have by the known formula, (A B)^Xsine AXsine (C+A) 2 sine C area, 1135.2.27.8 8th, by a similar formula from hav- ing A B, and the angles, B and C; area 1135.2.28.2 9th, by having C B and the angles, C and A; area 1135.3.03.58 10th, by having C B and the angles B and A: area 1135.3.04.38 40 The Surveyor's Guide. 11th, by a similar formula data C A, and the angles, C and B, gives the area 1135.0.39.66 12th, by a similar formula from da- ta C A, and the angles A and B; area 1135.1.00.12 13th, by data A BXB C, and the contained angle, we have A BXB CXsine B-1135.2.35.06 2 14th, by A CXA B, and the con- tained angle 1135.1.32.92 15th, by A CXB C, and their con- tained angle C 1135.2.00.79 16th, by data, A BXB C, and the angle, A, we have by a known formula, B AXsine A BC. =sine C, and A BXB C, sine (A+O) 2 area 1135.2.394 17th, by the application of similar formula to the data, A BXB C, and angle, C ; area 1135.2.30.4 The Surveyor's Guide. 41 18th, by A' CXC B, and angle, A, 1136.0.19.51 19th, by A CXB C, and angle, B, the area will be 1135.0.19.89 20th, by A CXB A, and angle, B, the area will be 1135.1.10.5 21st, by A CXB A, and angle, C, the area will be 1135.3.05.16 22d, by the usual rule from the three sides, s. s — a. s — b. s — c. 1135.2.14.7 Now the various data exhibited in this triangle have been ascertained with the same relative de- gree of precision ; and the different areas deduced therefrom have been subjected to the same loga- rithmic process, till the figure has been exhausted ; there is no reason to suppose that any one of them is nearer to the truth than another ; and taking a A. R. p. mean of the results we have 1135.2.12.97 for the nearest approximation to the true area. But suppose we consider the triangle as spheri- cal, and the admeasurement of the sides as the lengths of three arcs of three great circles of the sphere ; and, according to Sir Isaac Newton, the diameter of the earth to be 41,798,177 feet, we will then have, as the circumference of a great 4* 42 The Surveyor's Guide. -circle of the earth is to 360°, so is the length of C B to the number of degrees or minutes, &c., contained in the arch, C B, viz : As 131312964.37 And do. And do. 360°:: 11757.24 : l'.56".03868=archC A. do.:: 9664.38 :r.35".38309= " AB do. :: 10948.08 : r.48".05263== « B C. Now let b a c, represent the sides of any spheri- cal triangle, and e the spherical excess, we have by Lhuiller's theorem. Tangent ^ E= Tan. a+b+c. tan. a+b — c. tan. a — b+c. tan. — a+b+c. i 4 ' ~4 4 And by restoring to a b and c, their deter- mined values, we find a+b+c =0° .1' .19". 8686 a+b— c=0° .0' .32" .1771' a— b+c=0° .0' .21" .8493 And, — a+b+c=0° .0' .25" .842£ Whence the log. tangt. of 0° .1' .19" .8686= 6.5879531 of .0' .32" .1771= 6.1931205 of .0' .21" .8493= 6.0250065 of .0' .25" .8423= 6.0979010 2)24.9039811 Log. of i the spherical excess= 2.4519905 The arc corresponding to this log. will be found The Surveyor's Guide. 43 to be ,00584 parts of a second, consequently the spherical excess is 02336 of a second, and bj a well known theorem, As 180° : the area of one- quarter the surface of the sphere : : the spherical excess to the area of the spherical triangle, viz : As 180° 31500428420,3 the area of a great cir- cle of the earth in statute acres : : 023360 to A. R. p. 1135.2.11.3 being J perch less than the mean area, which is in defect, but should be in excess ; but this is accounted for by the hills on the land not being taken into account ; the difference, how- ever, is insignificant, and shows that the difference between a plane and spherical triangle of conside- rable dimensions is very inconsiderable. See Crib- son s Surveying ly Trotter. 28th. How to measure a tract of land by measu- ring a base line through it, and not departing from that line, and yet finding all the distances round the land, their courses, and angles of the field, and the area, never before published. In order to do this expeditiously, the surveyor should be provided with an instrument having two telescopes, one of which is movable, and the other fixed, by which he can at any time take half a right 44 The Surveyor's Guide. angle from the base line, and also a right angle ; he must also have an active assistant with a flag- staff, to hold at the corners as he proceeds with the measurement on the base line. Let ABODE T M G H A be any tract of land that is to be sur- veyed, let the base K L, be traced through it with a transit instrument, and poles set perpen- dicularly, to be visible from one to another. Set your instrument at L, on the base line, which in this survey bears N 40 E. A theodolite and com- pass attached is the best instrument for this method ; adjust your instrument, and let L be the point where 45° inflected from the base L K will cut the flag-staff; at the corner H, commence chaining towards K, and five chains you find 45° degrees deflected from the base line to the flag- staff at B, on the left, will bisect it, which note in your field-book by an oblique line to the left, ma- king an angle as near 45° as the eye can judge ; at 9.30 half a right angle to the right will cut a pole at G, and at 12.00 came the fence ; at 13.20 half C. L. a right angle will cut C, and at 19.15 you find a right angle will intersect H. Now it is evident C. L. that you are 19.15 distant from H, for H 19.15. L The Surveyor's Guide. 45 is an isosceles triangle, and .*. you mark 19.15 on the perpendicular. The next perpendicular is at 20, and the half right angle having been taken at c. 5 on the chain line, 20 — 5=15=the distance to B. 0. L. Again at 32.35 you find half a right angle bisects 46 The Surveyor's Guide. the pole at D, and at 33.20 a right angle inter- c. L. sects at G, and 33.20— 9.30-=30.40=the length of the perpendicular which set on it. At 34.20 you find the next perpendicular on the left to 0, and the one-half right angle having been taken at 13. 20 .-. 34.20— 13.20=21.o''o the distance to C ; pro- ceeding in this way you have 43.35 — 32.35=11 chains to D, and 51.30— 35,40=15.40=the dis- tance to M, and 57.40—38.30=19.10 to F, and 60— 5T.40=2.10=the perpendicular of the last A within the fence on the right and 62.30—60=2.30= the perpendicular without the fence ; also, 62.30 — 41=21. 30=the distance to E, which A is to be ducted out of the area of the last trapezoid on the left. Thus you have found with very little trouble all the requisites for calculating the area of the land, and it may be remarked, that you might have commenced at the corner B and noted where the two perpendiculars fell at 19.15 and 20 and as you proceeded on your base line take back sights at the proper distances to intersect the poles at B and H, and the distances from where the perpendicu- lars would fall to these several points would be the chains and links to be placed thereon. The dis- The Surveyor's Guide. 47 tances all round the land, can be accurately found, for in the present case n/(A a^)+(a H")= A H, and r Gr, and r H being given V{r G^)+(r IP)=H Gl- and so on all round the land, and seeing that the courses of A a and a H are given, the course of A H may be readily found, for having the distance and difference of latitude and departure, the course is given in the tables ; also, the internal angles can be easily found, for in the ^ A a H A a : Ead. : : a H : tang't a A H, and so with the A B b A. Hence, the angle B A H, is known, and it is evident the same holds good all round the land, the bases and perpendiculars of all the right angled triangles being found from the base line and can be marked on the sketch as the sur- veyor proceeds. The same may be done with a good compass, for having the course of the base line, the courses of the normals to right and left are known, and the course of J a right angle being once ascertained on the right and left of the base will always serve to find the points on the base where they are to be taken ; but this would require many trials and waste time, whereas, an instru- ment showing J a right angle will save much time. 48 The Surveyor's Guide. Thus, in a plane country, the scientific reader will acknowledge the plan completely available, and the surveyor can calculate the content of the land on the margin of his book while his needle is set- tling, and be able to answer the farmer satisfac- torily, who thinks a surveyor should be able to tell the content the moment he has the last distance measured. The plotting and calculation of a survey taken on the above plan is so obvious as to require no explanation, seeing all the figures are either right angled triangles or trapezoids, to find the area of which is shown in figure 12th. 29th. The most correct method of correcting the difierence of latitude and departure in surveys taken with the compass, to fit them for calculation, some authors divide the difi"erences proportionally among all the stations ; but as there may be some stations in a survey really correct, any alteration in them would make them incorrect, so that the altering of the legs of stations in surveys where land is of great value, is a matter of considerable importance. The Surveyor's Guide. 49 i^ Pig.] Problem. To find what may be the error in the difference of latitude and departure of a given station arising from the inacu- racy of practice : Let the right angled triangle A B D, fig. 18th, represent a station "with its difference of latitude and departure; if the angle A be the bearing, then will the leg A D, be the difference of latitude, and the leg B D, the departure ; but if the angle at B be the bearing, then will the leg B D, be the differ- ence of latitude, and D A the departure. Let the small angle B A b represent the error committed in taking the bearing, which may amount 7|- min- utes, and the small part B e or E b, the error com- mitted in chaining, in proportion to the whole line AB, or A e, as 0.5 is to 5.00, (for in measuring the 6 50 The Surveyor's Guide. length of lines, there may be an error committed of half a link in 10 chains ; (this is found by expe- rience), and let e a, b d, and E c be drawn parallel to B D, and B n o, and res, parallel to D A. Case 1st. Suppose A B to be the true bearing and length of a station, and A b the one found by observation. Now it is plain that instead of the triangle A B D, we shall have by observation the triangle A b d, so that there is an error of the quantity n b, by which the leg B D is increased, and an error of the quantity B n, by which the leg A D is decreased, and the contrary may be sup- posed, if A b be the true distance and bearing and A B that found by observation; but when the angle at A is very small, D d may be supposed equal to (0). Case 2d. Suppose the true length and bearing of a station to be A e, and that found by measur- ment to be A B the bearing exact. Now it is plain that the leg e a is increased by the error r B, and that the leg A a, is increased by the error r e or a D, and the quantities or errors by which each leg is increased are in proportion to the legs The Suevetor's Guide. 51 themselves, that is, B r : e a : : r e : A a, and as B e is to A e. Case Sd. Suppose A e the true bearing and length of a station, and A b the same, found by observation. This supposes a compound error both in chaining and bearing, and that the error in the bearing increases the smallest angle in respect of the bearing and its complement. Here we see that when the leg A a is increased to A D by the error in chaining, as in the last case, it shall, at the same time, be brought back to A d by the error in the bearing, as in case 1st. Therefore, the leg A a will be increased by the quantity r e — B n, or de- creased by the quantity B n — r e; but r e is greater than B n, when the angle at A is, small ; and B n is greater than r e, when the angle is near 45°; for they become equal when the angle is about 25°; but at the same time the leg e a will be increased to d b, by the error b S=b n+B r. Case 4th. Suppose A E the true distance and bearing, and A B that found by observation ; this supposes the error in the bearing to decrease the smallest angle. Now it is evident that the longer leg A c is increased by the error B o or D c, and 52 The Surveyor's Guide. the shorter leg decreased by the error E o. But B o=B n+r e (for r e=ii o) and E o=b n — B r. These errors are easily found in numbers by con- sidering the figure, and that they are always pro- portional to the length of the stations. Here follows a table of errors in links and deci- mals, calculated for a station of 30 two pole chains, and for the different angles and their com- plements, under which they are placed, but which can be changed to any other length, by altering them in the same proportion as are the stations. BAb=i°error in bearing. 88 ?2 78 23 67 32 58 42 48 45 B e 1.5 links error in chain- ing. bn= Bn= 3.2 0.0 3.1 0.7 3.0 1.4 2.8 1.7 2.2 2.3 2.3 Error in short Leg. ] Case Error in long Leg. J 1st. Br= r e= 0.0 1.5 0.3 1.5 0.6 1.4 0.8 1.3 1.0 1.1 1.0 1.0 Error in short Leg. ] Case Error in long Leg. J 2d. bs=(bn4-Br) ad=(Bn^re) 3.2 1.5 3.4 0.8 3.6 0.0 3.6 0.4 3.4 1.1 3.3 1.3 Error in short Leg. ) Case Error in long Leg. J 3d. Eo=(bn-B r) B o==(Bn+r e) 3.2 1.5 2.8 2.2 2.4 2.8 2.0 3.0 1.4 3.3 1.3 3.3 Error in short Leg. 1 Case Error in long Leg. J 4th. CORROLLARY. Hence we may adopt the following rules for altering the legs of stations in the correcting of surveys : The Surveyor's Guide. 53 Rule First. When the course, or angle, is either great or small ; or when the difference of latitude and de- parture are found in the beginning of the tables, then the shortest leg may be increased or decreased by any quantity not greater than 3.2 links, and the longest leg increased by any quantity not greater than 1.5 links. Rule Second. When the latitude and departure are found about the [middle of the tables, or when the angle is about 20° under or over 45°, then the shortest leg may be increased by any quantity not greater than 3.6, or rather 4 links, and the longest leg left unaltered, which is, when the error in the bearing increases the angle opposite the smallest side ; but when contrary, the longer leg may be increased by any quantity not greater than 3 links, and the shorter leg decreased by 2 links. Rule Third. When the difference of latitude and departure are found in the latter part of the tables, or when the bearing is about 45°, then either of the legs 54 The Surveyor's Guide. (they being nearly equal) may be increased or de- creased by any quantity not greater than 3 links, and the other leg by 1.4 links, but when one leg is increased the other must be decreased. These rules are on the supposition that the chaining is always too long, which, in practice, I have nearly always found to be the case ; but when a surveyor has reason to think otherwise, he may alter the rules to his opinion, not only in respect to this, but also relative to the quantity of the errors. A description of an instrument by which any person, though unskilled in surveying, may measure a map, or part of a map, almost at one view : Get a piece of good glass about 8 or 9 inches long, and 6 or 7 inches broad, and divide it into small oblong rectangles of eight-tenths of an inch by 5 five-tenths, as fig. 19th. By laying this in- strument (which I call a computor) on a map you can tell with very few figures, sometimes with the eye only, how many of the rectangles are con- tained in the map, and consequently, how many acres. When the map is laid down by a scale of 20 perches to an inch, then each rectangle will be The Surveyor's Guide. 55 16 perches by 10, or one acre ; and if the map be 40 perches to an inch, then each rectangle will be 32 perches by 20, or 4 acres ; and if by 80 per- ches to an inch, then each rectan- gle will contain 16 acres. This instrument would be useful to gentlemen and others not very well skilled in surveying, to measuriB a map, or part of a map that they wished to know the content of nearly. It is easily used. The sides of the ^^s- 19. glass must be made to coincide with as many of the lines on the map as possible, and the broken squares can be estimated by the eye, or a square inch horn. Description and design of a new instrument by wliicli dis- tances can be found at once, without any calculation ; Let a brass semi-circle (fig. 26) of about 9 inches radius, have its inner edge or limb, divided into 90 equal parts, beginning at N and counting up- wards 10, 20, 30, &c., to 90 at Z, and each of these divisions subdivided into 6 equal parts. Let 56 The Surveyor's Guide. the outer limb be divided into degrees and 6th parts of a degree, marking the degrees from the middle of the limb, both ways, 10, 20, 30, &c., to 90 at N and Z. Let also, the middle space be- tween the outer and inner limbs, be marked from Z to N, 10, 20, 30, 40, &c., to 180 at K Let this semi-circle be fixed to the middle of a box ruler B D, about S^ feet long, an inch and a half broad, and of a convenient thickness. The inner breadth of half this rule must be level with the surface of the semi-circle, but the outer half must be higher about two-tenths of an inch. On the outer half there must be fixed a thin brass scale of an equal length and breadth with the box ruler, the breadth of which scale is to be divided, by lines drawn from end to end, into three equal parts, and the length into inches, half inches, and tenth of an inch ; the inches are to be drawn di- rectly across the whole breadth, and marked 1, 2, 3, 4, &c., both ways to B and D ; the half inches are to be drawn across the middle and innermost third, and the lOths only across the inner third. Let there be on one end of this scale an inch, and on the other end half an inch, each divided very The Surveyor's Guide. 57 exactly into 10 equal parts diagonally, that the lOths and centesms which may happen in the operations, on the square and indices hereafter to be described, may be exactly measured on them by a pair of dividers. The reason for raising the outer half of the box ruler above the inner half two-tenths of an inch, is to make room for the in- dices A b and A d, which are to be fixed to the centre of the semi-circle, and there to open and shut as occasion requires, like the legs of a sector. Those indices are about 26 inches long, three- fourths of an inch broad, and about two-tenths thick; their breadth is to be divided into three equal parts, and their length into inches, half inches, and tenths, as the brass scale before men- tioned. The inches are to be marked from the center A, with 1, 2, 3, 4, &c., to b and d, and the tenths drawn across the inner third. Each of those indices must have a small screw nut with a pin or bit of wire upon it, which pin may, by the screw nut, be fixed exactly to any division on them in order to suspend the label, or ruler T Y, which has a thin piece of brass with a small hole in it, exactly fitting the aforesaid pin, and is to be fixed 58 The Sueveyor's Guide. also to any division of the ruler, as occasion re- quires. Let this label, or ruler, be about two feet long, and of the same breadth and thickness as the indices A b and A d, and divided after the same manner as they are, only the tenths are to be drawn across the inner edge, as well as across the inner third of the breadth, and the inches are to be marked 1, 2, 3, 4, &c., from C to T and Y, making C T eighteen inches, and C Y six. The like divisions are to be made on the side of the square K X, beginning at the inner edge of the brass ruler at K, marking the full inches on the upper side, 1, 2, 3, 4, &c., to 24 ; the tenths are to be drawn across the upper third and the upper edge. Let this instrument be fixed on a tripod with a ball and socket like those of a common sur- veying instrument, but very strong, in order to have it very firm ; and let there be sights which may, as occasion requires, be fixed on the diame- ter, indices, and ruler T Y, of the the same kind with those of a surveying instrument. N. B. The ball and socket must not be fixed exactly under the center of the semi-circle, but some distance from it, on the cross-bar which goes from The Surveyor's Guide. 59 the center to the middle of the limb, as -well to sup- port the head of the instrument more easily by be- ing nearer its center of gravity, as to make room for an air level, which must be fixed exactly under the diameter or ruler A B, so that when the semi- circle is turned vertically the diameter may be fixed horizontally. 60 The Surveyor's Guide. The use of the Instrument in measuring distances : Example. Let it be required to find the distance from the house at A to the castle, (fig. 27) or to any part thereof, as the weather-cock on the top of the spire at C. Having set up your instrument at A, turn it about till through the sights on the diameter, you see a mark set up at B, and having fixed the di- ameter in that position, turn the moving index till through the narrow slit of a small sight fixed on the center, you see the hair in the other sight cut the spire at C, then fixing the index in that posi- tion to the limb of the semi-circle, measure with a four pole chain in a straight line from A to B ; and having marked the chains and links of that distance on the diameter and placed the ruler with the sights on it exactly to that distance, by means of the small pin and hole mentioned before, set up your instrument at the end of the distance you measured (which you may make full chains if you please) and turn it about till through the sights on the diameter you see a pole at the first station A, and having fixed it in that position, turn the ruler on the pin which is fixed at the former distance on The Surveyor's Guide. 61 the diameter, till through the sights on it you see the vane at C ; then will the part of the index a c, cut by the inner edge of the ruler, give the dis- tance A C from the house to the spire at C, which was to be found ; and if there be occasion, the dis- tance from the mark at B to the spire will be found on the ruler at the intersection of the index ; all of which is plain from the similarity of the trian- gles ABC and a. pin. c, or that formed by the diameter, index, and ruler, from Cor. 1st 4 Euc. Book 6th. Thus the surveyor can find the distance of any or all the particular objects he can see and may wish to set down in his map, and by turning the instrument vertically by means of a notch in the socket, inaccessible heigths can, in like manner, be readily ascertained in the same manner. Example in Measuring Distance. Let it be required to find the distance from the house at A to the castle, (fig. 27) or to any part thereof, as the weather-cock at the top of the spire at C. Having set up your instrument at A, turn it about till through the sights on the diameter, you see a pole at B, and having fixed the diameter in 62 The Surveyor's Guide. that position, turn the moving index till through the narrow slit of a small sight fixed on the center, you see the hair in the other sight cut the spire at C ; then fix the index in that position to the limb of the semi-circle and measure with your chain of 100 links in a straight line from A to B, which mark on the diameter, and place the ruler, having the sights on it exactly on that distance by means of the small pin and hole before mentioned ; set up the instrument at the end of the measured dis- tance, and turn it about till through the sights on Pig. 27. the diameter you bisect the pole at A, and having fixed it in that position, turn the ruler on the pin which is fixed at the former distance on the diame- ter, till through the sights you see the vane at C ; then will the part of the index, a c, cut by the in- The Surveyor's Guide. 63 ner edge of the ruler, give the distance A C from the house to the spire at C. And in like manner by directing the ruler to any other objects from A, and noting the degrees cut by the ruler on the limb, and directing from B to each object, the distance from A vrillbe shown as before explained, and thus the surveyor fur- nished with such an instrument, can from the end of his first station, tell the length of his diagonals to as many corners as he can see from that point. Also, by turning the instrument vertically, heights can be determined in the same manner. I would recommend the surveyor to use a com- pass, having the limb divided into 360°, and the bottom of the box into four 90's ; then in taking the courses, if N. W., the limb and quarter com- pass are the same ; but if in the S. W. quarter, the sum of the degrees on the limb and quarter compass are 180° ; and in S. E. quarter, the dif- ference of the degrees on the limb and quarter compass make 180° ; lastly, if in the N. E. quar- ter, the sum of the quarter compass and limb make 360. A surveyor should prove all his courses by this rule before he quits his instrument. 64 The Sueveyor's Guide. Problem. Given the bearings of any two stations of a survey, thence to determine the angle made by those stations. Rule — Deduct the preceding bear- ing from the succeeding, according as the remain- der is greater or less than 180°. Add — or+180° (as the case may be) and you have the required angle. N. B. The angle found by the above rule will be internal if the polygon lie towards the right hand in the traverse ; and external, if toward the left. Example First. Required the several angles of the polygon A B C D E F G, the courses of the sides being, viz : Kg. 28. 1 A B 2691° or S. E. 891 2 B C 2511 or S. E. 711 3 C D 252f or S. E. 72| 4 D E 162^ or s. w. in 5 E F 77| or N.W. 77f 6 FG 30| or N.W. 30^ 7 GA 5f or N.W. 5f The Surveyor's Guide. 65 From 2511 From 77| take 269J take 162^ —18 —841 +180 +180 Sum 162=Ang. ABC. Sum 95i=Z. DBF From 252| From 30| take 2511 take 77f +li —47 +180 +180 Sum 1811=/. BCD. Sum 133=/: E F G From 162i From 5| take 252| take 30| —901 _25 +180 +180 Sum 891= A C D E. Sum 155=/. F G A From 2691 take 5| Rem. 2631 —180 Sum Now 180° multiplied by the number of sides 6* 66 The Surveyor's Guide. any polygon minus 360°, equals the sum of the in- ternal angles .-. 180X7= 160 and 1260—360=900 So 83|+162+181i+89J+95i+133+155=900°. Proof. Next. Having the bearing of any station and all the internal angles of any polygon, thence to determine the courses of each of the other stations in the regular order of succession, viz : the land lying to the right hand as you surround it. Rule : According as the given angle is+or — than 180° ; add the preceding bearing, succeeding angle, and +or — 180° (as the case may be ;) their sum will be the succeeding bearing or course. Note. — It sometimes happens that the result will be more than 360° ; in this case take 360° from it and the remainder will be the course of the succeeding station. Example. Take the course of A B 269i or S. 89i E, in the preceding figure, and the angles as there found, viz : The Surveyor's Gcjide. 67 269^ 162i 162 95J +180 +180 ^ 611J 4371 Deduct 360 360 Cou. of B C 251| or S TIJ E. Cou. of E F 77| or N 77f "W 251i 77f ISli 133 --180 +180 Cou. of C D 252f or S 72$ E. 390f 252f 360 fj Cou. of F G 30| or N 30| W +180 30| 522i 155 Deduct 360 +180 Cou. of D E 162i or S 17| W. 365f 360 Cou. of G A 5forN.5|W. 5f 83f +180 Cou. of A B 269 J or S 89 J E. being the' same as that given ; therefore, a proof of the correctness of the work. And thus the sur- veyor has a sure method of avoiding the inconve- nience of the needle being drawn from its true position by mines or other causes, and also correct the diurnal variation ; for no matter how much 68 The Surveyor's Guide. the needle may be attracted at any station, the angle will be correct by taking a back and fore sight at every station, and having the true course of the first station. All the others can be found by the foregoing rules. And to know if any at- traction exists at the first station, take a course in a different direction from your chain line ; go to the object bisected, or to some convenient distance in that direction, and take a back sight ; if that agree with the fore sight, you may safely conclude that no attraction exists at either ; but should it differ, make trial in some other direction, in like manner, till you find what station the attraction is in ; but by using a good theodolite all such trouble is avoided. In every survey that is truly taken, the sum of the Northings is equal to the sum of the Southings, and the sum of the Eastings to the sum of the "Westings. Let a b c e f g h represent a plot or parcel of land ; let a be the first station, b the second, c the third, and so on. Let N S be a meridian line, then will all lines parallel thereto, which pass through the The Surveyor's Guide. 69 y c 4 several stations, be aj meridians also, as a o, b s, c d, &c., and the lines b 0, c s, d e, &c., perpendiculars to these, will be east or west lines or de- n"T parture. The northings e i+g o+h g=a o+b s+ c d+f r, the southings ; for let the figure be com- pleted, then it is plain that g o+h g+r k=a o+ b s+c d and e i — r k=f r; if to the former part of this first equation e i— r k, be added, and f r to the latter, then g o+h g+e i=a o+b s+c d+f r ; that is, the sum of the northing is equal to the sum of the southings. The eastings c s+q a=o b+d e+i f+r g+o h, the westings for a q+y o (a z)=d e+i f+r g+o h, and h o=c s — y o. If to the former part of this first equation c s — y o, be added, and b o to the latter, then c s+a q=o h+d e+i f+r g+o h ; that is, the sum of the eastings is equal to the sum of the westings. Now, as there is many methods of calculation, and every man chooses one in preference to all 70 The Surveyor's Guide. others, I shall here show the method which I have always practiced, being, I think, least liable to mistakes, although not the shortest, as shall be hereafter shown. 1^ : : o : : : 1.00 2.00 2.00 2.00 1.00 s IJjj igllJ i : : : i ^ O -* iii 1 1! ilil i : : : 11 ogooooooooooooo g|§|§ :|g| :J : o sSsiijiiS lis o k 11^3333333331331 1 "Si rH « «) ■* >0 -iO i^- 00 OS C r-l 1.8410 0.7815 1.8376 0.7895 1.8341 0.7976 |l.8306 0.8055 2.7615 1.1722 2.7564 1.1842 2.7612 L1962 2.7469 1.2082 4 3.6820 1.5629 3.6762 1.5790 3.6682 L6960 3.6612 1.6110 5 4.6025 1.9537 4.5939 1.9737 4.5853 11.9937 4.5766 0.0137 fi 5.5230 2.3444 5.5127 2.3685 6.6024 2.3925 5.4919 2.4165*! 1 7 6.4435 2.7351 6.4315 2.7632 6.4194 2.7912 6.4072 2.8192 \ S 7.3640 3.1258 7.3603 3.1579 7.3365 3.1900 7.2226 3.2220 9 i 8.2845|3.5166 8.2691 'e.'w 3.6527 8.2636 3.5887 N. S. 8.2378 3.6247 N. S. e. W IN.S. N. S. E.W E.W J 114 The Surveyor's Guide. TABLES OF LATITUDE AND DEPARTURE. jl 1 1 N. S. E.W. N. S. E. W. 651 0.4107 N. S. E. W.| N. S. E. W. '"651" 0.4186 24 0.9135 66 24i 24i 65i 24i 0.4067 0.9117 0.9099 0.4147 0.9081 ?. 1.8271 0.8135 1.8235 0.8214 1.8199 0.8294 1.8163 0.8373 8 2.7406 1.2202 2.7353 1.2322 2.7299 1.2441 2.7244 L2560 4 3.6542 1.6269 3.6470 1.6429 3.6398 1.6588| 3.6326 1.6746 ft 4.5677 2.0337 4.5588 2.0536 4.5498 2.0735 4.5407 2.0933 1 6 5.4813 2.4404 5.4706 2.4643 5.4598 2.4882 5.4489 2.5122 7 6.3948 2.8472 6.3823 2.8750 6.3697 2.9029 6.3570 2.9306 1 ^ 7.3084 3.2539 7.2941 3.2857' 7.2797 3.3175 7.2651 3.3493 9 1 8.2219 3.6606 8.2058 3.6965 8.1896 3.7322 8.1733 3.7679 64i 1 0.4344 25° 65 25i 64i 25i 64i 25i 0.9007 0.9063 0.4226 0.9044 0.4265 0.9026 0.4305 1 8126 0.8452 |L8089 0.85311 1.8052 0.8610 1.8014 0.8688 3 2.7189 1.2679 2.7134 1.2797 2.7077 1.2915 2.7021 1.3032 4 3.6252 1.6905 3.6178 L7063 3.6103 1.7220 3.6028 1.7376 ft 4.5315 2.1131 4.5223 2.1328 4.5129 2.1525 4.5035 2.1720 fi 5.4378 2.5357 15.4267 2.5594 5.4155 2.5831 15.4042 2.6064 7 6.3442 2.9583 6.3312 2.9860 16.3181 3.0136 6.3049 3.0408 S 7.2505 3.3809 7.2356 3.4125 17.2207 3.4441 7.2056 3.4752 9 1 8.1568 .3.8036 8.1401 3.839] 8.1233 0.8949 3.8746 8.1063 3.9096 63i 0.4501 26° 64° 26i 634 0.4423 63i 26.! 0.8930 0.8988 0.4384 0.8969 0.4462 1.7976 0.8767 [1.7937 0.8846 !1.7899 0.8924 1.7859 0.9002 1 S 2.6964 1.3151 2.6906 1.3269 |2.6848 1.3386 2.6789 1.3503 4 3.5952 1.7535 13.5875 L7692 13.5797 1.7848 3.5719 1.8004 ft 4.4940 2.1919 14.4843 2.2115 4.4746 2.2310 4.4649 2.2505 6 5.3928 2.6302 15.3812 2.6537 5.3696 2 6772 5.3579 2.7006 7 6.2916 3.0686 .6.2781 3.0960 6.2645 3.1234 6.2508 3.1507 8 7.1904 3.5070 i7.1750 3.5383 7.1594 3.5606 7.1438 3.6008 9 1 8.0891 3.9453 _6_3_ 0.4540 18.0718 I'm' ' 0.8890 3.9806 0.4578 8.0544 4.0158 8.0368 4.0509 27i 62i- 0.4617 271 0.8850 62i 0.4056 0.8910 0.8870 ? 1 7820 0.9080 '1.7780 0.9157 1.7740 0.9235 1.7700 0.9312 3 2.0730 1.3620 2.6670 1.3736 ,2.6610 ,L3852 2.6550 1.3968 \ ^ 4 3.5640 L8160 3.5561 1.8315 3.5480 L8470 3.5400 1.8624 1 1 '"^ 4.4550 2.2699 4.4451 2.2894 4.4350 2.3087 4.4250 2.3281 1 fi 5.3460 2.7239 5.3341 2.7472 5.3221 2.7705 5.3099 2.7937 1 7 6.2370 3.1779 6.2231 3.2051 6.2092 3.2322 6.1949 3.2593 8 7.1280 .3.6319 7.1121 3.6030 7.0961 3.6940 7.0799 3.7249 9 8.0191 E.W. 4.0859 N. S. 8.0011 1 E.W. 4.1209 N. S. 7.9S31 4.1553 N. S.- 7.9049 !e. W. 4.1905 'n. S. E.W. The Surveyor's Gqide. 115 TABLES OP LATITUDE AND DEPARTURE 1 N. S. 28 0.8829 E. W. 62 0.4694 N. S. 28i E. AV.i 611 0.4733 N. S. E.W. N. S. 2SJ 0.8766 E.W. 28,^ 6U 61i 0.8809 0.8788 0.4771 0.4810 2 L7659 0.9389 L7618 0.9466 1.7576 0.9543 L7534 0.9620 3 2.64S8 1.4084 2.6427 1.4199 2.6364 1.4315 2.6302 1.4430 4 3.5318 L8779! 3.5236 L8933 3.5153 1.90S6 3.5069 1.9239 5 4.4147 2.3474 4.4045 3.3666 4.3941 2.3858 4.3836 2.4049 fi 5.2977 2.8168 5.2854 2.8399 5.2729 2.8629 5.2604 2.8859 7 6.1806 3.2863 6.1662 3.3132 6.1517 3.3401 6.1371|.3.3669 8 7.0636 3.7558 7.0471 3.78661 7.0305 3.8173 7.013S 3.8479 9 1 7.9465 4.2252 7.9280 4.2599 29J 1 60i 7.9093 4.2944 60i 7.8905 29i 0.8682 4.3289 29 61 0.4848 29i 0.8703 60i 0.8746 :0.S725 0.4SS6 0.4924 0.4962 2 L7492 0.9696] ,L7450 0.9772 1.7407 0.9848 1.7364 0.9924 3 2 6239 1.45441 ,2.6175 1.4659 2.6111 1.4773 2.6046 1.4886 4 3.4985 1.9392 3.4900 1.9545 3.4814 1.9697 3.4728 1.9849 5 4.3731 2.4240 4.3625 2.443 ll 4.3518 2.4621 4.3410 2.481] fi 5.2477 2.9089 '5.2350 2.93171 5.2221 2.9545 5.2092 2.9773 7 6.1223 3.3937 (6.1075 3.4203 6.0925 3.4463 6.0774 3.4735 S 6.997013.8785 6.9S00 3.9090i 6.9628 3.9394 7.9456 3.9697 9 1 7.8716J4.3633 7.8525 30i 0.8638 4.3976 , 59i i0.5038 7.8332 30i- 0.8616 4.4318 7.8138 30i 4.4669 30 60 0.5000 59i 0.5075 59i 0.S660 0.8594 0.5113 *? I.7320I1.OOOO L7277 !l.0076 1.7232 1.0151 L7188IL0226 8 2.59S1 1.5000 2.5915 1.5113 2.5849 1.5226 2.57S2;L5339 4 3.4041 2.2000 3.4552 2.0151 3.4465 2.0301 3.4376 2.0452 ,T 4.3301 2.5000 4.3192 2.5189 4.3081 2.5377 4.2970 2.5564 fi 5.1961 3.3000 5.1830 3.0226 5.1698 3.0452 5.1564 3.0677 7 6.0622 3.5000 6.0468 !3.5264 16.0314 3.5528 6.0158 3.5790 6.92S2 4.0000 6.9107 4.0302 6.8930 4.0603 6.8752 14.0903 9 1 7.7942 4.5000 59 0.5150 7.7745 31i 0.8549 4.5339 0.5188 :7.7547 4.5678 7.7346 31i 0.8503 4.6016 1-^ 0.8571 31i 68i 0.5225 58i 0.8526 0.5262 '>. 1.7143 L0301 1.709S 1.0375 L7053 L0450 1.7007 1.0524 q 2.5715 1.5451 2.5647 1.5563 2.5579 1.5675 2.5510iL5786 /| 13.4287 2.0602 3.4196 2.0751 3.4106 2.0900 3.4014 2.1048 5 14.2858 2.5752 4.2745 2.5939 4.2632 2.6125 4.251S 2.6311 fi 5.1430 3.0902 5.1295:3.1126 5.1158 3.1350 5.1021 3.1573 16.0002 3.6053 5.98443.6314 5.9685 3.6575 5.9525 3.6835 8 6.8573 4.1203 16.8393 4.1502 6.8211 4.1800 6.8028 4.2097 9 7.7145 4.6353 7.694214.0689 7.6738 4.7025 7.6532 4.7359 E. W N. S. E.W 1 N. S. E.W. 1 N.S. E.W 1 N.S. 116 The Surveyors Guide. TABLES OF LATITUDE AND DEPARTURE 1 N. S. E.W. 58° N. S. E.\Y. N. S. E.W. 57i 0.5373 N. S. 32i 0.8410 E.W. "67i" 0.6409 32° 0.8480 32i 0.8457 57S 32i 0.8434 0.5299 0.6336 2 1.6961 1.0598 L6914 1.0672 1.6868 1.0746 L6821 1.0819 •6 2.5441 L5897 2.5372 1.6008 2.6302 1.6119 2.5231 L6229 4 3.3922 2.1197 3.3829 2.1344 3.3736 2.1492 3.3642 2.1639 5 4.2402 2.6496 4.2286 2.6681 4.2169 2.6865 4.2052 2.7049. 6 5.0883 3.1795 5.0744 3.2017 5.0603 3.2238 5.0462 3.2458' 1 5.9363 3.7094 5.9201 3.7353 5.9037 3.7611 i 5.8873 3.7868 8- 6.7844 4.2394 6.7658 4.2689 6.7471 4.29841 6.7283 4.3278 9 1 7.6324 4.7693 7.6115 4.8026 56S 7.5905 4.8357 7.5694 33i 4.8688 '"56i 0.5566 33 57 33i 33i 0^8339 56^ 0.8386 0.6446 0.8363 0.6483 0.6519 0.8314 2 1.6773 L0893 1.6726 L0966 L6678 1.1039 1.6629 Lllll 3 2.5160 L6339 2.6089 1.6449 2.5017 1.6668 2.4944 L6667 4 3.3547 2.1786 3.3451 2.1932 3.3365 2.2077 3.3259 2.2223 5 4.1934 2.7232 4.1S14 2.7415 4.1694 2.7697 4.1573 2.7778 6 5.0320 3.2678 5.0177 3.2898 5.0033 3.3116 4.9888 3.3334 7 5.8707 3.8125 5.8540 3.8381 5.8372 3.8636 5.8203 3.8890 8 6.7094 4.3571 6.6903 4.3863 6.6711 4.4165 6.6618 4.4446 9 1 7.5480 4.9018 56° 7.5266 4.9346 7.5069 4.9674 7.4832 6.0001 34 34i 65S 34i 55i 0.5664 34S 56i 0.8290 0.5592 0.8266 0.5628 0.8241 0.8216 0.5700 2 L65S1 L1184 L6632 1.1256 1.6482 1.1328 1.6433 1.1400 1 3 2.4871 1.6776 2.4798 1.6884 2.4724 L6992 2.4649 1.7100 4 3.3162 2.2368 3.3063 2.2512 3.2965 2.2666 3.2866 2.2800 5 4.1452 2.7960 4.1329 2.8140 4.1206 2.8320 4.1082 12.8500 6 4.0742 3.3552 4.9595 3.3768 4.9447 3.3984 4.9299 13.4200 7 15.8033 3.9144 5.7861 3.9396 5.7689 3.9648 5.7515 3.9900 8 1 6.6323 4.4735 6.6127 4.5024 6.5930 4.5313 6.5732 4.5600 9 1 7.4613 ■350 5.0327 55 7.4393 5.0662 7.4171 35i 5.0977 54i 0.5807 7.3948 5.1300 "Hi" 0.6842 35i 541 351 0.8191 0.6736 0.8166 0.5771 0.8141 0.8116 1^ 1.6383 1.1472 1.6333 1.1543 1.6282 LI 614 1.6231 L1685 .S 2.4575 1.7207 2.4499 1.7314 2.4423 L7421 2.4347 1.7527 4 3.2766 2.2943 3.2666 2.3086 3.2565 2.3228 3.2463 2.3370 f> 4.0968 2.8679 4.0832 2.8867 4.0706 2.9035 4.0679 2.9212 fi 4.9149 3.4415 4.899? 3.4629 4.8847 3.4842 4.8694 3.5055 7 5.734] 4.0160 5.7165 4.0400 5.6988 4.0649 5.6810 4.0897 a 6.5632 4.5886 6.5331 4.6172 6.5129 4.6466 6.4926 4.6740 9 7.3724 6.1622 n". S. 7.349S 6.1943 7.3270 fETw: 5.2263 N. S. 7.3042 5.2582 NTs. E. W. N. S. E.W . The Surveyor's Guide. 117 TABLES OF LATITUDE AND DEPARTURE. j 1 ! 1 N. S. E.W. N. S. 36i 0.8064 E. AV. "63i~ 0.5913 N. S. E. W. 53i" N. S. E. W. •53i 0.5983 36 0.8090 64 364 36S 0.8012 0.6878 0.803810.5948 \ 2 1.6181 1,1766 1.6129 1.1826 1.6077|l.lS96 1.6025 1.1966 3 2.4271 1.7634 2.4193 1.7739 2.4116 1.7845 2.4038 1.7950 4 3.2361 2.3511 3.2268 2.3662 3.2154 2.3793 3.2050 2.3933 5 4.0451 2.9389 4.0322 2.9566 4.0193 2.9741 4.0063 2.9916 6 4.8641 3.6267 4.8387 3.6478 4.8231 1.3.6689 4.8075 3.5899 7 6.6631 4.1145 6.6461 4.1391 6.6270 4.1638 5.6088 4.1883 8 6.4721 4.7023 6.4516 4.7304 0.4308 4.7686 6.4100 4.7866 9 1 7.2812 6.2901 63 7.2580 6.3217 521 0.6053 7.2347 5.3534 7.2111 5.3849 52i 0.6122 37 0.7986 37J 37i 0.7933 62i 0.6087 371 0.7907 0.6018 0.7960 2 1.6973 1.2036 1.5920 1.2106 1.5867 1.2176 1.5814 1.2244 3 2.3959 1.8054 2.3880 1.8159 2.3801 1.8263| 2.3721 1.8366 4 3.1945 2.4073 3.1840 2.4212 3.17.34 2.4350 3.1628 2.4489 5 3.9932 3.0091 3.9800 3.0266 3.9668 3.0438 3.9534 3.0611 6 4.7918 .3.61091 14.7760 3.6318 4.7601 3.6526 4.7441 3.6733 7 5.6904 4.2127 15.5720 4.2371 5.6635 4.2613 5.6348 4.2855 8 6.3891 4.8145 6.3680 4.8424 6.3468 4.8701 6.3265 4.8977 9 1 7.1877 6.4163 7.1640 6.4476 7.1402 5.4788 7.1162 5.5099 38° 62 38i 611 1 0.6191 51i 0.6225 38i 61i' 0.6269 0.7880 0.6156 0.7853 0.7826 0.7799 2 1.5760 1.2313 1.5706 1.2382 1.5662 1.2450 1.5598 1.2518 3 2.3640 1.8470 2.3559 1.8673 2.3478 1.8676 2.3397 1.8778 4 .3.1520 2.4626 3.1413 2.4764 3.1304 2.4900 3.1195 2.5037 5 3.9401 3.0783 3.9266 3.0955 3.9130 3.1125 3.8994 3.1296 6 4.7281 3.6940 4.7119 3.7146 4.6956 3.736] 4.6793 3.7555 7 5.5161 4.3096 5.4972 4.3337 5.4782|4.3576 5.4692 4.3815 8 6.3041 4.9253 6.2826 4.9528 6.2608 4.9801 6.2391 6.0074 9 1 7.0921 6.5409 7.0678 5.5718 ToF 7.0434 6.6026 7.0190 6.6333 50i 0.6394 39° 61 0.62931 39i 0.7716 50i 0.6361 39i 0.7688 0.7771 0.7744 0.6327 9. 1.5543 1.2586 1.5488 1.2654 1.5432 1.2621 1.6377 1.2789 3 2.3314 1.8880 2.3232 1.8981 2.3149 1.9082 2.3065 1.9183 4 3.1086 2.5173 3.0976 2.6308 3.0865 2.64431 3.0764 2.6678 1 1 •"> 3.885713.1466 3.8719!3.1635| 3.858ll3.1804| 3.8442 3.1972 i 1 fi 4.6629 3.7759 4.6463 3.7962 4.6297 3.8165 4.613013.8366 j 1 ^ 5.4400 4.4052 5.4207 4.4289 5.4014 4.4525] 6.3819'4.4761 | 8 6.2172 5.0346 6.1951 6.0616 6.1730 6.08861 6.1507 5.1165 9 6.9943 5.6639 6.9695 5.6943 6.9446 5.7247 6.9196 E. W. 5.7650 E.W. N. S. E.W. N. S. E.W. N. S. N. S. 118 The Surveyor's Guide. TABLES OF LATITUDE AND DEPARTURE. [ 1 N. S. 40° 0.7660 E. W. 50 0.6428 N. S. E.W. N. S. E.W. N.S. E.W. 40i 0.-7632 49i m 49i 401 0.7676 49i 0.6461 0.7604 0.6494 0.6527 2 1.5321 1.2856 L5265 1.2922 1.5208 1.2989 1.5161 1.3055 '6 2.2981 1.9284 2.2897 L9384 2.2812 1.9483 2.2727 1.9583 4 3.0642 2.5711 3.0529 2.5845 3.0416 2.5978 3.0303 2.6110 1 ^ 3.8302 3.2139 3.8162 3.2306 3.8020 3.2472 3.787-8 3.2638 6 4.5963 3.8567 4.5794 3.8767 J4.5624 3.8967 4.6464 3.9166 7 5.3623 4.4995 5.3425 4.6229 6.3228 4.6461 6.3029 4.6693 8 6.1284 5.1423 6.1059 5.1690 |6.0832 5.1956 6.0605 5.2221 9 1 6.8944 5.7851 6.8691 5.8151 481 6.8436 6.8460 48i 6.8181 5.8748 48i 6.6659 41 49 41i 0.7518 m 411 0.7460 0.7547 0.6560 0.6593 0.7489 0.6626 2 1.5094 1.3121 L5037 1.3187 1.4979 1.3252 L4921 1.3318 3 2.2041 1.9682 2.2555 1.9780 2.2468 L9879 2.2382 1.9976 4 3.0188 2.6242 3.0074 2.6374 2.9958 2.6505 2.9842 2.6635 5 3.7735 3.2803 3.7592 3.2967 3.7447 3.3131 3.7303 3.3294 6 4.5283 3.9364 4.5110 3.9660 4.4937 3.9757 4.4764 3.9953 7 5.2830 4.5924 6.2629 4.6154 6.2426 4.6383 5.2224 4.6612 8 6.0377 5.2485 [6.0147 6.2747 5.9916 6.3010 5.9686 6.3270 9 1 6.7924 5.9045 6.7666 5.9341 6.7406 5.9636 6.7145 '42i 6.9929 42 48 0.6691 42i 0.7402 471 0.6723 ,0.7373 m 0.676-6 47i 0.7431 0.7343 0.6788 2 1.4863 1.3383 1.4804 1.3447 11.4740 1.3512 1.4686 1.3576 3 2.2294 2.0074 '2.2207 2.0171 2.2118 2.0268 2.2029 2.0364 4 2.9726 2.6765 2.9609 2.6895 2.9491 2.7024 2.9373 2.7152 5 3.7157 3.34571 3.7011 3.3618 3.6864 3.3779 3.6716 3.3940 6 4.4589 4.0148 4.4413 4.0342 4.4237 4.0535 4.4059 4.0728 7 5.2020 4.6839 5.1815 4.7066 6.1610 4.7291 5.1402 4.7516 8 15.9452 5.3530 5.9218 5.3789, 5.8982 6.4047 6.874616.4304 || 9 6.6883 6.0222 47 6.6620 0.7283 6.0513 46i 0.6852 6.6355 1 43i 6.0803 6.6089 6.1092 1 43 0.7313 m\ 431 0.7223 46i 0.69i5 0.6S2oi 0.7253'0.6883| ;^ 1.4627 1.3640| 1.45G7 1.3704 1.4507 1.3767 1.4447 1..3830 3 2.1941 2.0460 2.1851 2.05561 ;2.1761 2.0651 2.1671 2.0745 !j 4 2.9254 2.7280 2.9135'2.7407; '2.9015 2.7534 2.8894 2.7660 1 5 3.6568 3.4100 3.6418 3.4259| 3.6269 3.4418 3.6118 3.4576 || 6 i4.3881 4.09201 4.3702 4.1111 4.3622 4.1301 4.3342 4.1491 7 5.1195 4.7740 5.0986 4.7963 5.0776 4.8186 6.0565 4.8406 i 8 5.8508 5.4560 5.8269 6.4814 6.8030 6.5068 6.7789 5.5321 1 9 6.5822 6.1380! 6.5553 6.1666 N. S. 6.5284 E.W. 6.1952 6.6013 6.2236 N.S. 1 E. W. N. S. E. W. N. S. E.W. The Surveyor's Guide. 119 tables of latitude and departure. I 1 N". S. E.W.I N. S. E.W. N.S. E.W. 45J N. S. E.W. 1 44° 46 Ui 45i 0.7132 44i 45i 0.7040 0.7193 0.6946 0.7163 0.6978 0.7009 0.7102 2 1.4387 1.3893 1.4326 1.3956 1.4266 1.4018 1.4204 1.4080 ■6 2.1580 2.0840 2.1489 2.0934 2.1397 2.1027 2.1306 2.1120 4 2.8774 2.7786 2.8652 2.7912 2.8630 2.8036 2.8407 2.8161 5 3.5967 3.4733 3.5815 3.4889 3.5662 3.5045 3.5509 3.5201 6 4.3160 4.1679 4.2978 4.1867 4.2795 4.2054 4.2611 4.2241 1 5.0354 4.8626 5.0141 4.8845 4.9927 4.9063 4.9713 4.9281 8 5.7547 5.5573 5.7304 5.5823 5.7060 5.6072 5.6816 5.6321 9 1 6.4741 6.2519 6.4467 6.2801 6.4192 6.3081 6.3917 6.3361 46 45 0.7071 0.7071 2 1.4142 1.4142 3 2.1213 2.1213 4 2.8284 2.8284 5 3.5355 3.5355 6 4.2426 4.2426 7 4.9497 4.9497 8 5.6569 5.6569 9 6.3640 6.3640 b7W. E.W. N. S. N. S. E.W. N. S. E.W. N. S. TAELES OP SUEYEYS THE USE OP THE FOREGOING TABLES IN RELATION TO SURVEYS. They show, by inspection, the alteration of lati- tude and departure to every degree on the com- pass, and that for any distance not exceeding 100.000 links. In the uppermost rank of every division are placed the several angles and their complements, to 45°, including the quarter, half, and three- quarters of degrees ; and in the left-hand column are lengths of the measured lines of the field- work, and in the common areas are the difference of latitude and departure. Examples. Suppose the angle to be N. E. 27J degrees, and the line in the field measured to 6 chains, and it be required to find the Northings and Eastings of that station, under 27J degrees, and answering to 6 in left-hand column, the number in the com- (120) The Surveyor's Guide. 121 mon area, 5.3221, -which shows the Northings ; and under 621, (which is the complement to that angle) opposite the same number in the side col- umn, I find 2.7705, which shows the Easting of that station. If the course be the same, and dis- tance 60 chains, remove the decimal point one place to the right-hand, and the latitude and de- parture will be 53.221 27,705. And if the line were 600 chains, the course remaining the same, the Northings would be 532 chains, 21 links, and the Eastings 277 chains, 05 links. If the measured line doth not consist of an ex- act number of tens, as suppose its length to be 75 chains, 03 links, or 75 chains, 34 links, and the course 27J° ; then under this angle, and opposite c. 70 are 62.091 6 " 4.435 0.30 links 0.266 0.04 " 0.035 70 chains 32.822 5 " 2.308 0.30 links 0.138 0.04 " 0.018 Northing. 66.827 Easting 34.786 for 75 chains, 34 links. for 75 chains, 34 links. And so for any other. N. B. These tables will answer to ^° or 7J', an arithmetical mean between |° and J°, or between J° and f °. Ailjr;\/-.4, PUBLICATIONS HENRY CAREY BAIRD, SUCCESSOR TO B. L. CAREY, , 7 Hart's Building, Sixlh Street above Chestnut, Philadelphia. SCIENTIFIC AND PRACTICAL. 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