LIBRARY OF THE UNIVERSITY OF ILLINOIS AT URBANA-CHAMPAIGN 510.84 ho. £1-80 >3 CO Digitized by the Internet Archive in 2013 http://archive.org/details/singularshockswi70chow UNIVERSITY OF ILLINOIS GRADUATE COLLEGE DIGITAL COMPUTER LABORATORY REPORT NO. 70 SINGULAR SHOCKS WITH STRAIGHT BRANCHES by Y. S. Chow September 15, 1955 This work has been supported by the National Science Foundation under Grant G-1221 I. Introduction The purpose of this report is to discuss the situation which arises in a two-dimensional stationary or pseudo- stationary flow when a shock front consists of one straight shock and one analytic curved shock. All the notations used below have the same meaning as those given in (l), unless they are defined explicitly. We shall suppose the flow is polytropic and the flow ahead of the shock is uniform, i.e. all the flow quantities u, , u p , m, p, $ are constants ahead of the shock. Let the shock configuration in a two-dimensional pseudo- stationary (stationary) flow at time t he represented by the equations x. = ta. (s ) 1 1 i = 1,2. [x. = a.(s)] where x, and x are fixed Cartesian coordinates in the plane in which the shock is moving, and s is a parameter along the shock which may be chosen so that a! (s)a!(s) = 1, where li 7 da (s) (s) = ds at regular points . We shall assume that at time t each point of the region behind the shock with a singularity is occupied by a single fluid particle which has crossed the shock at some time t earlier than t. Let s^ be the value of s corresponding o * " to the singular point of the shock and call the singularity as the point § , and ■jfr Jg. y y y denote all the values of flow variables at s by u, , u , f , c . ro • Behind the shock, the streak line S of s^ and one of the characteristics at s , C, divide the whole region into three parts I, II and III, say, see Figure 1. In part I, the flow is uniform, for the shock front is straight there and the flow ahead of UNIF. I *S UNIF, -+► CL. the shock is uniform. In part III, the flow is non-isentropic, rotational, for the shock front is curved there and the flow ahead of the shock is uniform. In part II, the flow is irrotational and isentropic, since the flow is continuous in crossing C. The boundary S is a (2) slip-stream , and in stationary case, C is a straight line. -1- II. The Coordinate System in Part I Let the shock front be x. = ta.(s), a< (s )a / . (s ) = 1 , 1 1 ' 11 ' where a. ; (s) = 0, when s > s^ + 0. n = 2, 3, k, . . . . a ) n *(s) = when s < s - 0, n ■ 2, 3, k, . . ., N-l, but a! N ^(s-) ^ for i = 1 or 2, 3b.(s,r) and let — — = u. - b.(s.r), b.(s,0) = a.(s). then in Part I, u. = constants, b.(fe, 1 &') = u. + (a.(s) - u. )e ' i ' i ' 11 i Let T be the arc length of a.(s,Z") for fixed s, and T = when + ~ ^ J ^ |.Va:(s) = const.] ( 2. 3 ) v -^ 2 2(a ; (s)(a (s) - u)) 2 [ a! (s ) (a (s ) - u )] = (1 -J.) 2 + [a!(s)(a (s) - u )| 2 h§| - -^ ) v/A ii x \/A 3 A 2 3a bt^ = - ( a i (s) - \)^r -2- a^ a:(sj [a.(s) - u. ]fo(s)(a.(s) - u.)j 3T \TST \/~A : (s,T) - u_ a (s) - u, a 2 (s,T) - a 2 (s) u p From (2.1) we have r — =r = 7— r I / r fa \ 7 — r = — a 1 (fe,T) - u x a 1 (s) - 1^ I a^e/r) - a 1 (s) 1^ Therefore the streak lines in part I are straight and lie on the straight lines passing through the points (s,0) and (u,,u ) . Put y - a + p, — . Then U 2 a g (s) - u 2 if 2 2 2 /° tan J = 77- = — 7 — v = independent of T. [r = indep. of s and T if U-, a, \s ) — U-, ~* c. V n, 3T 11 = 0, n = 1,2, .... "»% 9n / 2 From (2.2) / U . = \.U. = -(l t 11 w- L Ss n 3T" [a.(s)(a.(s) - u.y = 0, n = 1,2, (2.5) U, = const •] (2.6) U n = Wl - [-iW(«teW " U 2 ] " »2 (s)(a l< 8 > - V] (1 - jff f' [U = L. n const, 3 as T=0 ■If 5 8s n T=0 = 3\ = 0, 2^ 5^ aT = a 2j dT + c 2 g ig c \ COS |1 3s : 2 mc U n aV ^U a'(s)(a (s) - u ) 3T y/X ' 8T n = 0. n = 2, 3, ^, ... n = 3, 4, (2.7) (2.8) (2.9) -3- 9U. Q _ 9a. U.U. U i pT V ^T U i 3T V il=- i £>T g - O] (2.10) L3T By rotating the coordinate axes of a-.,a p plane we can always suppose that the straight shock is parallel to the a p axis, i.e.: a, (s) = a = const, a (s) = s, when s > s^. a,' (s) = 0, a'(s) = 1, when s > s*. Then t \t \ i <\2 (a - u , )(s - u ) T (s - Up) H = -7Ti T ' ^ = 1 -^r + ^r- T U t - - (■ - u 2 )(l - $-), n = - (a - Ul ){l - ^) 2 s - u . fk D - AT + (s - u ) T Tan |i = — , tan a = —? r? c= , a - u, , _T_ (a - u n )(s - u Q )T ' 1 ■*■ " u (s - Ug) - (a - u x ) T sin »* = 7T\ > cos ^ = ~uk (1 • W ] A i 2T / x2 T 2 / x2 = 1 - - (a - u x ) + - (a - u x ) III. The Boundary C Between Part I and Part II. /~~2 r^ n r ds _ , _ sin u i vm - 1 cos u. On C, s = ^ = - a + , where a + = — *• - —* — — A.(l - m cos \i) In (s,T) plane, the image of Figure 1 is as the following Figure 2. -h- From Figure 1, we know s* >u , s* > u _ 2 : - "1 (V*<°' ^nC< cos n* < 0, sin u* < , -r For the shock front is continuous at s , hence cos |t* < 0, sin |i* <0 Figure 2 2 2 1 - m cos n > -Of* < - Q!* — + Therefore C is a C -characteristic, i.e. along C, we have s= -a . For psuedo- stationary flow, suppose on a curve F: x. = tb. (fe,T) which lies in I and on which m E 1> then V a c = const. Also by (2.2) we have, along F, £Y_ ' __J__ _ S " U 2 dT ~ " e/A~ " /3T s - 1 = - X sin i4«s -1 = 3 = X sin (-L On the other hand a. = + K sin p. s = - a Therefore F is a characteristic. Now suppose m* = 1, then V = c, i.e. V =v/A"- T = /(a - U;L ) 2 + (s - Ul )' - T = c -5- gives a relation between s and T, therefore it determines a curve in a, ,a p plane, on which V =/( a;L (s,T) - u x ) 2 + (a 2 (s,T) - u 2 )' = c i.e. it determines a sonic circle; this circle should he the boundary C, because the existance of C through each point is unique. For stationary case, if m* = 1 then m = 1 in part I, so m = 1 does not give an equation of a curve. But in this case, on the boundary C we still have m = 1, and C is a straight line. For both stationary and pseudo-stationary cases, if m* = 1, then we have proved that, along C m = 1, therefore along C, we have: ij I id \ sin n , n . n a. sin \i 1 cot |i 1 1 n cot [i 1 (3-D The only shock configurations with singularity which can exist are those such that [i, (11.20)] B N+1 A N+1 = ij J (3-2) where A 11 A 11 A. = A. .a ., „ 2 .2 am sin n a i " r+ 1 ' 2 /-, 1 sin u.\ /^„\ -^n (i - — s + ■ —n) ( >o ) 2 " f-\ m 2 implies * sec (i • r+ i 2 . -l * cr sm |i = i.e. tan \i* = 2 2 1 - (m* cos u*) = sin |i* > 0, tan n* ^ 0. Therefore we get a contradiction. Hence, for N = we have m* f 1. For N > 0, if m* =1 the conditions (3-2) are always satisfied, therefore we can possibly have the case m* = 1. • IV. Stationary Case , (m > l) In part I, j, and y p are constants; so are they on the boundary C. By the result on j_III, p. 60^ , in a neighborhood of C in part II, the flow is a simple wave, i.e. 5, = f(j p ) for some function f. Suppose the flow in part II is analytic then the flow in the whole region II is simple. Because C is a C , the flow in Part II is a /_ wave (i.e., the image of part II in J,, J_ plane lies on a certain characteristic /_ in J,, 7 p plane) and along each C in part II J , and j are constants [[ill, p. 60-6l~] . Therefore by Bernolli's law, V is constant along every C in part II, for the flow there is isentropic, and u, and u p are constants along every characteristic C in part II. Applying the result proved on [ill, p. 60J , we know every C in II is a straight line. •7- In II every C cannot intersect C. (otherwise passing through some point on C there exist two C 's), so it must intersect the boundary S. For p, j, u, , u p , c, m are all constants along C in II, therefore, if we know all these values on S, we know the flow in II. On S we have: a.(s*,T) = a i (s^) + a^(s^,0) T + a J (s^,0) ^7 + where 'hv'i ■ Si a^s.T) _) s T = 8, = o : a:( s ^,o) -^ T = = cos 3 2 s = s = sin T if i = 1, if i = 2 * ..-^ aJ(s^O) = -sin J 2 -K =0 (i = l) = cos fZ'*** = ° (i = 2) a N (s^ ,0) = - sinf* •K^ 1 =0 (i = l) = cos f* •K^ 1 =0 (i = 2) a ( s„, 0; = - sm = cos fa'** (i = 1) (i = 2) In a small neighborhood of s^, we can omit all the terms whose power are greater than N+2, then we have i x ( s^T) = a + cos f* T - sin f* • K^~ ^gyi _* * * ,pN+2 a 2 ( s^T) = s* + sin f£ T + cos ^ • ^" J^l (*.l) -8- where K. = Ap k„ which can he calculated. / „ . <° *- TT la* *N *- T (f 2 (8„T) -f a+ K„ fr=?2 +A 2 S. IT f ^i) - £ ♦ *« * I (u - 2) For the flow in part II is isentropic and irrotational, so we can deter- mine c(s ,T), and hy Bernolli's relation we can find the value of V(s ,T). There- fore we can determine u,(g^,T) = V cos jp, u ? (s^,T) = V sinjl. Thus we know the values of the flow variahles on the stream line S. By the result proved in LlII, p. ^2 J , we know the direction of the characteristic C at each point on S. For C is straight, so we know the C itself. Along every C the flow variahles are constants, so we can determine the flow in part II if we know the singular shock and the uniform flow ahead of the shock. V. The determination of the Curved Shock . (Stationary Case) (m > l) Now we try to discuss another question: If we are given a uniform flow ahead of a singular shock and a simple flow *r = f (j, ) in part II, then what can we say ahout the curvature and the derivative of curvatures at the singularity B # ? Tauh [i, (8.2) and (8.8)] proved that ^(s,0) = ka, (5.1) 9s i 2 2 2m sin 2u 2 /n 1 sinuu where ^ = r+1 . * 2 = yTT (l - ^ + ~^) — = = A. . — nT = kA. .a. = kA! on the shock. (5.2) ^T ij 5>S ij J 1 KS i In part II, f 2 = t(f^) 1 ■h ...tSh = f 0. Hence where a p sinh© + d coshO = d sinh© + a p cosh©, .'. a = d. (5«6) /m* - 1 2/m 2 - 1 . _ , , Q /~2 I" = r— a, = — : — Bin 2u, tanh© =v/ m - 1 cot u.. 21)^+1 ' m If k~ = k~ = = k" x = 0, k^ ^ 0, then 9 "5l * f 2 „ f/t"/ s>r* T " * p ^ + l "I'o^l By Tauh [i, (9.4) and (9. 5) J, we have, at s , a N+1 5. 1 - A? +1 k7„, (5.8) jH+1 - "i "(H) (Ml./SlM) =Q ( > A 2 m a sinh (N + 1) + d cosh (N + l) = d sinh (N + l) + a p cosh (N + l) a 2 = d. (5.IO) -10- On the shock: 1 2 f 9 2 . „ 2 ■ ,r, \ - — = -s — 7 ( ;r~ m .sin 2 M- + m — - sin 2pJ gs <>r+ i v ps CK ps 2 _ 2 / 1 ^m 3 / glnjx x ^s r+ 1 I" m 3 ps ^s k ^2 ; By Taub [i, (8.1), (8.5)] we have t:-^i > S-* (v!-^- 1 -^)-'^-) 2 2 2+Jjr- i)^- 2 m cos jj. = * — {r+ 1) + 2 ( "then B 2 - ftfjU^f - fC-f^B 2 = (5-1^) -•* and we cannot determine k By the same reasoning as before, we can suppose ^U JT ^T = A?k + 3kk n B? + k 3 C? 3 i 2 1 i i Differentiating (5«3) twice and using (5.15), we have 3k kl (B3 _ fn{ fj A l A 2 . fl{ Jj B 3) + k 3 (c 3 _ f m ( f i)(A l)3 . 3f ,. ( jP ) A 1 B 2 (5.16.) - f (f 1 ).c^) = o (5.17) If k~* 4 0, and B^ - f"(^)ATA^ - f'CJ'' )B^ ^ 0, we can determine k" for given k" _•* _ * Similarly we can get relations for k , k , -12- Bibliography 1. Taub, A.H., Determination of Flows Behind Stationary and Pseudo-Stationary Shocks, Annals of Mathematics, 62:300-325 (1955) 2. Taub, A. H. Singularities on Shocks, American Math. Monthly, 61:11-12 (195*0 3. Courant and Friedrichs, Supersonic Flow and Shock Waves, Intersciences, p. 60 (19^8) -13-